Caluculate the density of uranium `-235` nucleus. Given `m_(n) = m_(p) = 1.67xx10^(-27) kg`.

Explanation

Mass of uranium 235 = No. of nucleous `xxm_("nucleon")`
`= A xx 1.67xx10^(-27)kg`
Also volume of nucleus `= (4)/(3)pi r^(3)`
`= (4)/(3) pi (1.3xx10^(-15)xx A^(1//3))^(3)`
(where `A` is mass no.)
`= 9.2xx10^(-45) xx A m^(3)`
`:. "Density" = (m)/(V) = (1.67xx10^(-27)xx A)/(9.2xx10^(-45)xx A)`
`= 1.8xx10^(17)kg m^(-3)`