Two radioactive elements `X` and `Y` half-live pf `50` and `100` minute respectiv ely. Intial sample of both the elements have same number of atoms. The ratio of the reamaining number of atoms of `X` and `Y` after 20 minute is:

Options

A. `2`
B. `1//2`
C. `4`
D. `1//4`

Answer

`(d)`

Explanation

For `X:200 = (2.303xx50)/(0.693) log ((a)/(x_(1)))`
For `Y: 200 = (2.303xx100)/(0.693) log ((a)/(x_(2)))`
`:. (x_(1))/(x_(2)) = (1)/(4)`