Molar volume is the volume occupied by 1 mole of any (Ideal) gas at standard temperature and pressure (STP , `0^(@) C`, 1 atmospheric pressure). Show that it is 22.4 litres. Take `R = 8.31 J mol^(-1) K^(-1)`.

Explanation

Here, `P=1 atm. = 0.76 m of Hg`
`= 0.76 xx (13.6 xx 10^(3)) xx 9.8 Pa`
`T=273 K, R=8.31 J "mole"^(-1) K^(-1),`
`V=? , mu = 1 "mole"`
As , `PV=mu R T or V=(mu RT)/(P)`
`:. V=(1 xx 8.31 xx 273)/(0.76 xx (13.6 xx 10^(3))xx9.8)`
`=22.4 xx 10^(-3)m^(3) = 22.4 litre`.