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Number of electron involved in the reduc...

Number of electron involved in the reduction of `Cr_(2)O_(7)^(2-)` ion in acidic solution to `Cr^(3+)` is:

A

`0`

B

`2`

C

`3`

D

`5`

Text Solution

Verified by Experts

The correct Answer is:
C
In this reaction three electrons are required for the reduction of `Cr_(2)O_(7)^(2-)` into `Cr^(3+)`.
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