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If `f:[1,10]->[1,10]` is a non-decreasing function and `g:[1,10]->[1,10]` is a non-decreasing function. Let `h(x)=f(g(x))` with `h(1)=1,` then `h(2)`

A

lies in (1,2)

B

is more than two

C

is equal to one

D

is not defined

Text Solution

Verified by Experts

The correct Answer is:
C
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