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A stationary body explodes into two frag...

A stationary body explodes into two fragments of masses `m_(1)` and `m_(2)`. If momentum of one fragment is `p`, the energy of explosion is

A

`(p^(2))/(2(m_(1)+m_(2)))`

B

`(p^(2))/(2 sqrt(m_(1)m_(2)))`

C

`(p^(2)(m_(1)+m_(2)))/(2m_(1)m_(2))`

D

`(p^(2))/(2(m_(1)-m_(2)))`

Text Solution

Verified by Experts

The correct Answer is:
C
`E = E_(1) + E_(2) = (p_(1)^(2))/(2 m_(1)) + (p_(2)^(2))/(2m_(2))`.
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