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The radionuclide .^(56)Mn is being produ...

The radionuclide `.^(56)Mn` is being produced in a cyclontron at a constant rate `P` by bombarding a manganese target with deutrons. `.^(56)Mn` has a half-life of `2.5 h` and the target contains large numbers of only the stable manganese isotopes `.^(56)Mn`. The reaction that produces `.^(56)Mn` is
`.^(56)Mn +d rarr .^(56)Mn +p`
After being bombarded for a long time, the activity of `.^(56)Mn` becomes constant, equal to `13.86 xx 10^(10) s^(-1)`. (Use `1 n2=0.693`, Avagardo number `=6 xx 10^(2)`, atomic weight of `.^(56)Mn=56 g mol^(-1)`).
At what constant rate P, `.^(56)Mn` nuclei are being produced in the cyclontron during the bombardment?

A

`2xx10^(11) "nuclei"//s`

B

`13.86xx10^(10) "nuclei"//s`

C

`9.6xx10^(10) "nuclei"//s`

D

`6.93xx10^(10) "nuclei"//s`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • The radionuclide .^(56)Mn is being produced in a cyclontron at a constant rate P by bombarding a manganese target with deutrons. .^(56)Mn has a half-life of 2.5 h and the target contains large numbers of only the stable manganese isotopes .^(56)Mn . The reaction that produces .^(56)Mn is .^(56)Mn +d rarr .^(56)Mn +p After being bombarded for a long time, the activity of .^(56)Mn becomes constant, equal to 13.86 xx 10^(10) s^(-1) . (Use 1 n2=0.693 , Avagardo number =6 xx 10^(2) , atomic weight of .^(56)Mn=56 g mol^(-1) ). After a long time bombardment, number .^(56)Mn nuclei present in the target depends upon.

    A
    All (i), (ii), and (iii) are correct.
    B
    Only (i) and (ii) are correct.
    C
    Only (ii) and (iii) are correct.
    D
    Only (i) and (iii) are correct.
  • The radionuclide .^(56)Mn is being produced in a cyclontron at a constant rate P by bombarding a manganese target with deutrons. .^(56)Mn has a half-life of 2.5 h and the target contains large numbers of only the stable manganese isotopes .^(56)Mn . The reaction that produces ^(56)Mn is .^(56)Mn +d rarr .^(56)Mn +p After being bombarded for a long time, the activity of .^(56)Mn becomes constant, equal to 13.86 xx 10^(10) s^(-1) . (Use 1 n2=0.693 , Avagardo number =6 xx 10^(2), atomic weight of .^(56)Mn=56 g mol^(-1) ). After the activity of .^(56)Mn becomes constant, number of .^(56)Mn nuclei present in the target is equal to .

    A
    ` 5xx 10^(11)`
    B
    ` 20 xx 10^(11)`
    C
    ` 1.2xx 10^(14)`
    D
    ` 1.8 xx 10^(15)`
  • log_(a)(mn) is equal to

    A
    `n log_(a) (m)`
    B
    `log_(a)m xx log_(a)n`
    C
    `log_(a)m + log_(a)n`
    D
    `log_(a)m - log_(a)n`
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