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Helium nuclei combine to form an oxygen ...

Helium nuclei combine to form an oxygen nucleus. The energy released in the reaction is if `m_(O)=15.9994 "amu"` and `m_(He)=4.0026 "amu"`

A

`10.24 Me V`

B

`0 Me V`

C

`5.24 Me V`

D

`4 Me V`

Text Solution

Verified by Experts

The correct Answer is:
A
`Deltam= 4m_(He)-m_(0)`
`Deltam= 0.01 "amu" " " DeltaE=DeltaMC^(2)=0`
binding energy per`//`Nucleon`=176//16"amu"=10.24 meV`
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Knowledge Check

  • Helium nuclei combines to form an oxygen nucleus. The energy released per nucleon of oxygen nucleus is if m_(0)=15.834 amu and m_(He)=4.0026 amu

    A
    `10.24 MeV`
    B
    0MeV
    C
    `5.24 MeV`
    D
    4 MeV

  • Helium nuclei combines to form an oxygen nucleus. The energy released per nucleaon of oxygen nucleus is [if m_(0)=15.834 amu "and" m_(He)=4.0026 amu ]:

    A
    `10.24 MeV`
    B
    `0 Mev`
    C
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    D
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    A
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    B
    (b) 56.12 MeV
    C
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