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Starting with a sample of pure .^(66)Cu,...

Starting with a sample of pure `.^(66)Cu, 7//8` of it decays into `Zn` in `15` minute. The corresponding half-life is:

A

`10` minute

B

`15` minute

C

`5` minute

D

`7(1)/(2)`minute

Text Solution

Verified by Experts

The correct Answer is:
C

`N=N_(0)(1-e^(-lambdat))`
`rArr (N_(0)-N)/(N_(0))=e^(-lambdat)`
`:. (1)/(8)=e^(-lambdat)`
`rArr 8=e^(lambdat t)" "rArr 3 ln 2=lambda t " "rArr=(3xx0.693)/(15)`
`t_(1//2)=(0.693)/(3xx0.693)xx15" "t_(1//2)=5 min`
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