The vapour pressure of chlorobenzene and water at different temperature are
`{:(t//^(@)C,90,100,110),(P^(@)(phiCI)//mmHg,204,289,402),(P^(@)(H_(2)O)//mmHg,526,760,1075):}`
(A)At what pressure will `phiCl` steam-disillation at `90^(@)C`?
(B)At what temperature will `phiCl` steam-dissillation under a total pressure of `800 mm Hg`?
(C) How many grams of steam are required for distillation of `10.2g` of `phiCl` (i)at `90^(@)C` and (ii) under `800` torr total pressure?

Answer

(A)`730mm Hg.` (B)`approx92^(@)C`, (C) `4.13gm,4.14gm`

Explanation

(A) At `90^(@)C`,
Pressure at which `phiCl` steam `-` distil
`=P^(@)(phiCl)+P^(@)(H_(2)O)`
`=204+526=730 mm` of `Hg`
(B) At `90^(@)C`
Total `P_(T)=730mm Hg`
At `100^(@)C` total `P_(T)=289+760=1049 mm Hg`
so for `800 mm Hg`, temperature will lie in between `90^(@)-100^(@)C`
Using extrapolation method.
Temperature `=90+((800-730))/((1049-730))xx(100-90)=92.19^(@)C`.
(C) (i) `(P_(phiCl)^(@))/(P_(H_(2)O)^(@))=(n_(phicl))/(n_(H_(2)O))`
`(204)/(526)=(10xx18)/(112.5xxm)`
`m=4.13gm`
(ii) At `800` tprr `T=92^(@)C`
For `phiCl,(p-204)/(92-90)=(289-204)/(100-90)`
`P=572.8`
For `H_(2)O,(p-526)/(92-90)=(760-526)/(100-90)`
`P=572.8`
`(10xx18)/(112.5xxm)=(221)/(572.8 rArrm=4.14gm`