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Show that the time for attaining half th...

Show that the time for attaining half the value of the final steady current in LR-series circuit is `0.693(L//R)`.

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Knowledge Check

  • In L-C-R series circuit

    A
    current may achieve same value for two different value of frequency
    B
    current can not achieve same value for two different values of frequency
    C
    current is maximum for a maximum value of frequency
    D
    none of these

  • The current in the series L-C-R circuit is

    A
    `i=i_(m)sin(omegat+phi)`
    B
    `i=(v_(m))/(sqrt(R^(2)+(X_(c)-X_(L))^(2)))sin(omegat+phi)`
    C
    `i=2i_(m)cos(omegat+phi)`
    D
    Both (a) and (b)

  • At resonance the peak value of current in L-C-R series circuit is

    A
    `E_(0)//R`
    B
    `(E_(0))/(sqrt(R^(2) + (omega L - (1)/(omega C))^(2)))`
    C
    `(E_(0))/(sqrt(R^(2) + (omega L - (1)/(omega^(2) C^(@)))^(2)))`
    D
    `(E_(0))/(sqrt(2)R)`

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    Show that the sum of instantaneous currents during growth and decay of current in LR circuit is independent of time.

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