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What happens when ethylbenzene is heated...

What happens when ethylbenzene is heated with acidified `K_(2)Cr_(2)O_(7)` ?

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To solve the question "What happens when ethylbenzene is heated with acidified K2Cr2O7?", we can follow these steps: ### Step 1: Identify the Reactants We start with ethylbenzene, which has the following structure: - Ethylbenzene consists of a benzene ring (C6H5) with an ethyl group (C2H5) attached to it. ### Step 2: Understand the Reagent The reagent used is acidified potassium dichromate (K2Cr2O7). In acidic conditions, K2Cr2O7 acts as a strong oxidizing agent. ...
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Knowledge Check

  • SO_(2) reduces acidified K_(2)Cr_(2)O_(7) to

    A
    `Cr_(2)(SO_(4))_(3)`
    B
    `CrO_(3)`
    C
    `Cr_(2)O_(3)`
    D
    chromium
  • Hydrogen sulphide truns an acidified K_(2)Cr_(2)O_(7)

    A
    colorless
    B
    green
    C
    pink
    D
    orange
  • When SO_(2) is passed through acidified K_(2)Cr_(2)O_(7) solution

    A
    the solution turns blue
    B
    the solution is decolourised
    C
    `SO_2` is reduced
    D
    green `Cr_2(SO_4)_3` is formed.
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