Home
Class 12
PHYSICS
Analternating voltage E= E0 sin omegat i...

Analternating voltage `E= E_0 sin omegat` is applied to a circuit containıng a resistor R connected in series with a black box. The current in the circuit is found to be `=I_(0) sin (omegat+pi//4)`.

State whether the element in the black box is a capacitor or inductor.

Text Solution

Verified by Experts

As the current leads the voltage by ,`pi/4` the element used in black box is a ‘capacitor’.
Promotional Banner

Topper's Solved these Questions

  • SAMPLE QUESTION PAPER 2019

    CBSE COMPLEMENTARY MATERIAL|Exercise Section C|19 Videos
  • SAMPLE QUESTION PAPER 2019

    CBSE COMPLEMENTARY MATERIAL|Exercise Section C|19 Videos
  • ELECTROSTATICS AND CURRENT ELECTRICITY

    CBSE COMPLEMENTARY MATERIAL|Exercise NUMERICALS|49 Videos
  • UNIT–III & UNIT–IV MAGNETIC EFFECTS OF CURRENT AND MAGNETISM & E.M.I. AND ALTERNATING CURRENT

    CBSE COMPLEMENTARY MATERIAL|Exercise (NUMERICALS)|57 Videos

Similar Questions

Explore conceptually related problems

An voltage, E = E_(0) sin omega t is applied acorss an inductor L. Obtain an expression for the current.

An alternating voltage E=E_0 sin omega t , is applied across a coil of inductor L. The current flowing through the circuit at any instant is

A small signal voltage V(t)=V_(0)sin omegat is applied across an ideal capacitor C :

An alternating voltage V = V_(0) sin omegat is applied across a circuit. As a result, a current I = I_(0) sin (omegat – p/2) flows in it. The power consumed per cycle is