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Analternating voltage E= E0 sin omegat i...

Analternating voltage `E= E_0 sin omegat` is applied to a circuit containıng a resistor R connected in series with a black box. The current in the circuit is found to be `=I_(0) sin (omegat+pi//4)`.

State whether the element in the black box is a capacitor or inductor.

Text Solution

Verified by Experts

As the current leads the voltage by ,`pi/4` the element used in black box is a ‘capacitor’.
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Analternating voltage E= E_0 sin omegat is applied to a circuit containıng a resistor R connected in series with a black box. The current in the circuit is found to be =I_(0) sin (omegat+pi//4) . Draw the corresponding phasor diagram and find the impedance in tems of R.

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Knowledge Check

  • If an alternating voltage V=V_0 sin omegat is applied across an inductance I, the current through the inductance will be

    A
    `I = I_0 sin omegat`
    B
    `I = I_0 sin(omegat+pi//2)`
    C
    `I = I_0 sin(omegat+pi//2)`
    D
    `I = I_0 sin(omegat+pi)`

  • If an alternating voltage V=V_0 sin omegat is applied across an inductance I, the current through the inductance will be

    A
    `I = I_0 sin omegat`
    B
    `I = I_0 sin(omegat+pi//2)`
    C
    `I = I_0 sin(omegat+pi//2)`
    D
    `I = I_0 sin(omegat+pi)`

  • A small signal voltage V(t) = V_(0)sin omegat is applied across an ideal capacitor C

    A
    Current l(t) leads voltage V(t) by `180^(@)`
    B
    Current l(t) lags voltage V(t) by `90^(@)`
    C
    Over a full cycle the capacitor C does not consume any energy from the voltage source
    D
    Current l(t) is in phase with voltage V(t)

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