Home
Class 12
PHYSICS
An electron travels on a circular path o...

An electron travels on a circular path of radius 10 m in a magnetic field of `2 xx 10^(–3)` T. Calculate the speed of electron. What is the potential difference through which it must be accelerated to acquire this speed?

Text Solution

AI Generated Solution

To solve the problem, we need to calculate the speed of an electron moving in a magnetic field and the potential difference required to accelerate it to that speed. ### Step 1: Understand the relationship between magnetic force and centripetal force When a charged particle like an electron moves in a magnetic field, it experiences a magnetic force that acts as a centripetal force, keeping it in circular motion. The magnetic force \( F \) on a charged particle moving with speed \( v \) in a magnetic field \( B \) is given by: \[ F = qvB ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • UNIT–III & UNIT–IV MAGNETIC EFFECTS OF CURRENT AND MAGNETISM & E.M.I. AND ALTERNATING CURRENT

    CBSE COMPLEMENTARY MATERIAL|Exercise LONG ANSWER QUESTIONS (5 Marks)|5 Videos

  • SAMPLE QUESTION PAPER 2019

    CBSE COMPLEMENTARY MATERIAL|Exercise Section C|19 Videos

Similar Questions

Explore conceptually related problems

An electron travels in a circular path of radius 20cm in a magnetic field 2xx10^-3T (i) Calculate the speed of the electron (ii) What is the potential difference through which the electron must be accelerated to acquire this speed? Charge of electron =1*6xx10^(-19)C . Mass of electron =9xx10^(-31)kg .

An electron is revolving in a circular path of radius 2xx10^(-10) m with a speed of 3xx10^(6) m/s. The magnetic field at the centre of circular path will be-

Knowledge Check

  • An electron revolves in a circular orbit of radius r with angular speed omega . The magnetic field at the centre of electron orbit is

    A
    `(mu_(0) e omega)/(pi r)`
    B
    `(mu_(0)e omega)/(4pir)`
    C
    `(mu_(0) e^(2) omega)/(4 pi r)`
    D
    `(mu_(0) e omega)/(2pi r )`

  • An alpha particle travels in a circular path of radius 0.45 m in a magnetic field B = 1.2 Wb//m^(2) with a speed of 2.6xx10^(7) m//sec . The alpha particle is

    A
    `1.1xx10^(-5) sec`
    B
    `1.1xx10^(-6) sec`
    C
    `1.1xx10^(-7) sec`
    D
    `1.1xx10^(-8) sec`

  • An electron is moving on a circular path of radius r with speed v in a transverse magnetic field B. e/m for it will be

    A
    `v/(Br)`
    B
    `B/(rv)`
    C
    `Bvr`
    D
    `(vr)/B`

    • Similar Questions

    Explore conceptually related problems

    An alpha particle moves along a circular path of radius 2Å with a uniform speed of 2xx10^6ms^-1 . Calculate the magnetic field set up at the center of circular path.

    An electron is moving with a velocity of 10^(7) ms^(-1) on a circular path of radius 0.57 cm in a magnetic field of 10^(-2) Wbm^(-2) . Find the value of e//m for the electron.

    A deuteron (the nucleus of an isotope of hydrogen) has a mass of 3.34 xx 10^-27 kg and a charge of +e . The deuteron travels in a circular path with a radius of 6.96 mm in a magnetic field with magnitude 2.50 T . (a) Find the speed of the deuteron. (b) Find the time required for it to make half of a revolution. (c) Through what potential difference would the deuteron have to be accelerated to acquire this speed?

    An electron having kinetic energy 10eV is circulating in a path of radius 0.1 m in an external magnetic field of intensity 10^(-4) T. The speed of the electron will be

    An electron moves along a circular path of radius 10 cm. If the centripetal acceleration is 4xx10^(11) m//s^(2) , then its linear speed is

    Home
    Profile