Double bond equivalents help in search f...

Double bond equivalents help in search for structure of a compound. It involves following steps:
Calculate the expected number of hydrogen atoms in the saturated structure.
(a) For `C_(n)` there would be: `(2n+2)` hydrogens if compound contains C,H,O only.
(b) For `C_(n),N_(m)` there would be `(2n+2+m)` hydrogens.
Subtract the actual number of hydrogen and divide by 2. This gives the double bond equivalents.
Ring is considered to possess single DBE.
Double bond equivalent of `C_(7)H_(16)O` would be

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Double bond equivalents help in search for structure of a compound. It involves following steps: Calculate the expected number of hydrogen atoms in the saturated structure. (a) For C_(n) there would be: (2n+2) hydrogens if compound contains C,H,O only. (b) For C_(n),N_(m) there would be (2n+2+m) hydrogens. Subtract the actual number of hydrogen and divide by 2. This gives the double bond equivalents. Ring is considered to possess single DBE. Double bond equivalent of benzene will be:

`{:("Compound",DBE),(C_(7)H_(10)O,2):}`

`{:("Compound",DBE),(C_(7)H_(8)O,4):}`

`{:("Compound",DBE),(C_(7)H_(17)N,3):}`

`{:("Compound",DBE),(C_(7)H_(13)NO,2):}`