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Double bond equivalents help in search f...

Double bond equivalents help in search for structure of a compound. It involves following steps:
Calculate the expected number of hydrogen atoms in the saturated structure.
(a) For `C_(n)` there would be: `(2n+2)` hydrogens if compound contains C,H,O only.
(b) For `C_(n),N_(m)` there would be `(2n+2+m)` hydrogens.
Subtract the actual number of hydrogen and divide by 2. This gives the double bond equivalents.
Ring is considered to possess single DBE.
Double bond equivalent of `C_(7)H_(16)O` would be

A

2

B

3

C

4

D

1

Text Solution

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The correct Answer is:
A
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Double bond equivalents help in search for structure of a compound. It involves following steps: Calculate the expected number of hydrogen atoms in the saturated structure. (a) For C_(n) there would be: (2n+2) hydrogens if compound contains C,H,O only. (b) For C_(n),N_(m) there would be (2n+2+m) hydrogens. Subtract the actual number of hydrogen and divide by 2. This gives the double bond equivalents. Ring is considered to possess single DBE. Double bond equivalent of benzene will be:

Double bond equivalents help in search for structure of a compound. It involves following steps: Calculate the expected number of hydrogen atoms in the saturated structure. (a) For C_(n) there would be: (2n+2) hydrogens if compound contains C,H,O only. (b) For C_(n),N_(m) there would be (2n+2+m) hydrogens. Subtract the actual number of hydrogen and divide by 2. This gives the double bond equivalents. Ring is considered to possess single DBE. Which of the following is not correct?

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Knowledge Check

  • Double bond equivalents help in search for structure of a compound. It involves following steps: Calculate the expected number of hydrogen atoms in the saturated structure. (a) For C_(n) there would be: (2n+2) hydrogens if compound contains C,H,O only. (b) For C_(n),N_(m) there would be (2n+2+m) hydrogens. Subtract the actual number of hydrogen and divide by 2. This gives the double bond equivalents. Ring is considered to possess single DBE. Double bond equivalent of benzene will be:

    A
    2
    B
    3
    C
    4
    D
    1

  • Double bond equivalents help in search for structure of a compound. It involves following steps: Calculate the expected number of hydrogen atoms in the saturated structure. (a) For C_(n) there would be: (2n+2) hydrogens if compound contains C,H,O only. (b) For C_(n),N_(m) there would be (2n+2+m) hydrogens. Subtract the actual number of hydrogen and divide by 2. This gives the double bond equivalents. Ring is considered to possess single DBE. Which of the following is not correct?

    A
    `{:("Compound",DBE),(C_(7)H_(10)O,2):}`
    B
    `{:("Compound",DBE),(C_(7)H_(8)O,4):}`
    C
    `{:("Compound",DBE),(C_(7)H_(17)N,3):}`
    D
    `{:("Compound",DBE),(C_(7)H_(13)NO,2):}`

  • Maximum number of hydrogen bonding in H_(2)O is

    A
    1
    B
    2
    C
    3
    D
    4