When a nucleus with atomic number `Z` and mass number `A` undergoes a radioactive decay process,
(i) Both `Z` and `A` will decrease, if the process is `alpha` decay
(ii) `Z` will decrease but `A` will not change, if the process is `beta^(+)-`decay
(iii) `Z` will increase but `A` will not change, if the process is `beta-`decay
(iv) `Z` and `a` will remain uncharged, if the prices is `gamma` decay

Options

A. both Z and A will decrease, If the process is `alpha` decay
B. Z will decrease but A will not change, if the process is `beta^(+)` decay
C. Z will decrease but A will not change, if the process is `beta^(-)` decay
D. Z and A will remain unchanged, if the process is `beta` decay

Answer

A, B, D

Explanation

`alpha` decays : `._(2)He^(4)`, so both Z & A decreases. `beta^(+)` decays : `._(+1)e^(0)`,
so A will not change but Z will change (decreases) `beta^(-)` decat : `._(-1)e^(0)`,
so A will not change but Z will change (increases) `gamma` decays : no change in A & Z.