Home
Class 12
PHYSICS
Let (nr) and (nb) be respectively the nu...

Let `(n_r) and (n_b) be respectively the number of photons emitted by a red bulb and a blue blub of equal power in a given time.

A

`n_(r) = n_(b)`

B

`n_(r) lt n_(b)`

C

`n_(r) gt n_(b)`

D

data in insufficient

Text Solution

Verified by Experts

The correct Answer is:
C

`P_(r)=(n_(r)hc)/lambda_(r), P_(b)=(n_(b)hc)/lambda_(b)`
if `P_(r)=P_(b)` Since `lambda_(r) gt lambda_(b) implies n_(r) gt n_(b)`
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Exercise - 34|2 Videos
  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Exercise - 36|2 Videos
  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Exercise - 28|2 Videos
  • RACE

    ALLEN|Exercise Basic Maths (Wave Motion & Dopplers Effect) (Stationary waves & doppler effect, beats)|25 Videos
  • TEST PAPER

    ALLEN|Exercise PHYSICS|4 Videos

Similar Questions

Explore conceptually related problems

Two bulbs 'A' and 'B' emit red light and yellow light at 8000 "Å" and 4000 "Å" respectively. The number of photons emitted by both the bulbs per second is the same. If the red bulb is labelled as 100 watts, find the wattage of the yellow bulb.

If n_(r ) and n_(b) are the number of photons of red and blue light respectively with same energy, then

Two bulbs A and B are emitting monochromatic light of wavelength such that A can just ionise H atom and B can just ionise He^(+) ions. If the power of A and B are 30 W and 40 W respectively , the ratio of number of photons emitted per second by bulb A to bulb B is :

n_(R) and n_(g) give the number of photons in red and green beams of light. If the two beams have the same energy, then

The maximum number of photons emitted when an electron jumps from an energy level n=5 to n=1 is s

The maximum number of photons emitted when an electron jumps from an energy level n=4 to n=1 is

A bulb of 40 W is producing a light of wavelength 620 nm with 80% of efficiency , then the number of photons emitted by the bulb in 20 seconds are : ( 1eV = 1.6 xx 10^(-19) J , hc = 12400 eV )

When the intensity of a light source is increased (a) the number of photons emitted by the source in unit time increases (b) the total energy of the photons emitted per unit time increases (c) more energetic photons are emitted (d) faster photons are emitted

Two sources A and B have same power . The wavelength of radiation of A is lambda_a and that of B is lambda_b .The number of photons emitted per second by A and B are n_a and n_b respectively, then