In a Coolidege tube experiment, the minimum wavelength of the continuouse X-ray spectrum is equal to `66.3` om . Then

Options

A. electrons accelerate through a potential difference of `12.75 kV` in the Coolidge tube
B. electrons accelerate through a potential difference of `18.75 kV` in the Coolidge tube
C. de-Broglie wavelength of the electrons reaching the anticathode
is of the order of `10 "pm"`
D. de-Broglie wavelength of the electrons reaching the anticathode is `0.01 Å`

Answer

B

Explanation

`V=(12400)/(lambda_(min))xx10^(-10)` volt
`V=(12400xx10^(-10))/(66.3xx10^(-12))` volt `=12.4/66.3 xx10^(4)=18.75 kV`