Home
Class 12
PHYSICS
Two protons are having same kinetic ene...

Two protons are having same kinetic energy. One proton enters a uniform magnetic field at right angles ot it. Second proton enters a uniform electric field in the direction of field. After some time their de Broglie wavelengths are `lambda_1 and lambda_2` then (a) `lambda_1 = lambda_2` (b) `lambda_1 lt lambda_2` (c) `lambda_1 gt lambda_2` (d) some more information is required

A

`lambda_(1) = lambda_(2)`

B

`lambda gt lambda_(2)`

C

`lambda_(2) gt lambda_(1)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D

We have work is done by only electric field. Thus if `bar(E)||vec(v),|vec(v)|` decreases, & thus momentum of electron decreases & vice-versa, while in magnetic field `|vec(v)|` remains constant.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Exercise - 36|2 Videos
  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Exercise - 37|2 Videos
  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Exercise - 32|2 Videos
  • RACE

    ALLEN|Exercise Basic Maths (Wave Motion & Dopplers Effect) (Stationary waves & doppler effect, beats)|25 Videos
  • TEST PAPER

    ALLEN|Exercise PHYSICS|4 Videos

Similar Questions

Explore conceptually related problems

If the two roots of the equation (lambda-2)(x^2+x+1)^2-(lambda+2)(x^4+x^2+1) are real and equal for lambda=lambda_1,lambda_2 then lambda_1+lambda_2=0 (b) |lambda_1-lambda_2|=6 (c) lambda_1+lambda_2=32 (d) all of these

Let be the maximum kinetic energy of photoelectrons emitted by light of wavelength lambda_(1) and lambda_(2) correspondingto wavelength lambda_(2) . If lambda_(1) = 2lambda_(2) then:

Knowledge Check

  • Two electrons are moving with the same speed v. One electron enters a region of uniform electric field while the other enters a region of uniform magnetic field,then after sometime if the de-Broglie wavelenths of the two are lambda_(1) and lambda_(2) then :

    A
    `lambda_(1) =lambda_(2)`
    B
    `lambda_(1) gt lambda_(2)`
    C
    `lambda_(1) lt lambda_(2)`
    D
    `lambda_(1) gt lambda_(2)` or `lambda_(1) lt lambda_(2)`
  • A proton and an electron are accelerated by same potential difference have de-Broglie wavelength lambda_(p) and lambda_(e ) .

    A
    `lambda_(e ) = lambda_(p)`
    B
    `lambda_( c ) lt lambda_(p )`
    C
    `lambda_( e ) gt lambda_( p ) `
    D
    none of these
  • The wavelength of electron waves in two orbits (lambda_(1) : lambda_(2))

    A
    `25 : 9`
    B
    `5 : 3`
    C
    `9 : 25`
    D
    `3 : 5`
  • Similar Questions

    Explore conceptually related problems

    An electron, a doubly ionized helium ion (He^(+ +)) and a proton are having the same kinetic energy . The relation between their respectively de-Broglie wavelengths lambda_e , lambda_(He^(+)) + and lambda_p is :

    Some energy levels of a molecule are shown in the figure. The ratio of the wavelengths r = lambda_1//lambda_2 is given by -

    A dye absorbs a photon of wavelength lambda and re - emits the same energy into two phorons of wavelengths lambda_(1) and lambda_(2) respectively. The wavelength lambda is related with lambda_(1) and lambda_(2) as :

    Two sound waves of wavelengths lambda_(1) and lambda_(2) (lambda _(2) gt lambda_(1)) produces n beats//s , the speed of sound is

    For balmer series wavelength of first line is lambda_(1) and for brackett series wavelength of first line is lambda_(2) then (lambda_(1))/(lambda_(2)) is