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Find bond enthalpy of S-S bond from the ...

Find bond enthalpy of S-S bond from the following data:
`C_(2)H_(5)-S-C_(2)H_(5)," "DeltaH_(f)^(@)=-147.2kJ" "mol^(-1)`
`C_(2)H_(5)-S-S-C_(2)H_(5)," "DeltaH_(f)^(@)=-201.9kJ" "mol^(-1)`
`S(g)," "DeltaH_(f)^(@)=222.8kJ" "mol^(-1)`

A

`-168.1 KJ//"mol"`

B

`+168.1 KJ//"mol"`

C

`-277.5 KJ//"mol"`

D

`+277.5 KJ//"mol"`

Text Solution

Verified by Experts

The correct Answer is:
D
`C_(2)H_(5)-S-C_(2)H_(2)+Srarr C_(2)H_(5)-S-S-C_(2)H_(5)`
`DeltaH_(f)^(@)(C_(2)H_(5)-S-C_(2)H_(5))=DeltaH_(f)^(@)(C_(2)H_(5)_S-S-C_(2)H_(5))-DeltaH_(S-S)-DeltaH_("sub")S.`
`DeltaH_(S-S)=277.5 KJ//"mol"`
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The bond dissociation energy of a diatomic molecule is also called bond energy. However, the bond dissociation energy depends upon the nature of bond and also the molecule in which the bond is present. The bond energy N-H bind in NH_(3) is equal to one-third of the energy of dissociation of NH_(3) because there are three N-H bonds and those of C-H bond in CH_(4) is equal to one-fourth of the energy of dissociation of CH_(4) Heat of a reaction = Bond energy of reactants - Bond energy of products Find the bond enthalpy of S-S bond from the following data. C_(2)H_(5)-S-C_(2)H_(5)(g) " " Delta H_(f)^(@) = -147.23 kJ mol^(-1) C_(2)H_(5)-S-S-C_(2)H_(5)(g) " " Delta H_(f)^(@) = -201.92 kJ mol^(-1) S(g) Delta H_(f)^(@) = 222.80 kJmol^(-1)

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