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Find the quantum number n corresponding ...

Find the quantum number `n` corresponding to the excited state of `He^(+)` ion of on transition to the ground state that ion emits two photons in succession with wavelengths `108.5` and `30.4nm`.

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The correct Answer is:
5
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Find the quantum number n corresponding to the excited state of He^(+) ion, if on transition to the ground state that ion emits two photons in succession with wave lengths 108.5 and 30.4 nm .

Find the quantum number n corresponding to the excited state of He^(Theta) ion if on transition to the ground state that ion emits two photon in succession with wavelength 108.5 and 30.4 nm

Find the quantum number n corresponding to nth excited state of He^(++) ion if on transition to the ground state the ion emits two photons in succession with wavelength 108.5 nm and 30.4 nm. The ionization energy of the hydrogen atom is 13.6 eV.

Find the quantum number n corresponding to the excited state of He^(+) ion if on transition to the ground state that ion emits two photons in succession with wavelengths state that ion emits two photons in succession with wavelengths 1026.7 and 304Å. (R = 1.096 xx 10^(7)m^(_1)

Find the quantum of the excited state of electrons in He^(+) ion which on transition to first excited state emit photons of wavelengths 108.5 nm . (R_(H)=1.09678xx10^(7) m^(-1))

A 100 eV electron collides with a stationary helium ion (He^(+)) in its ground state and excites to a higher level. After the collision , He^(+) ion emits two photons in succession with wavelength 1085 Å and 304 Å . Find the principal quantum number of the excite in its ground state and. Also calculate energy of the electron after the collision. Given h = 6.63 xx 10^(-34) J s .

Knowledge Check

  • Find the quantum of the excited state of electrons in He^(+) ion which on transition to first excited state emit photons of wavelengths 108.5 nm . (R_(H)=1.09678xx10^(7) m^(-1))

    A
    `6`
    B
    `5`
    C
    `4`
    D
    `2`
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