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Let M be a 3xx3 non-singular matrix with...

Let M be a `3xx3` non-singular matrix with det(M)=`4,"If" M^(-1)"adj(adjM)=k^(2)I`, then the value of 'k' may be

A

`+2`

B

4

C

`-2`

D

`-4`

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The correct Answer is:
To solve the problem, we need to find the value of \( k \) given the equation \( M^{-1} \text{adj}(\text{adj} M) = k^2 I \) for a non-singular \( 3 \times 3 \) matrix \( M \) with \( \text{det}(M) = 4 \). ### Step-by-Step Solution: 1. **Understanding the Given Information:** We know that \( M \) is a \( 3 \times 3 \) non-singular matrix, which means its determinant is not zero. We are given that \( \text{det}(M) = 4 \). 2. **Using the Formula for Inverse:** The inverse of a matrix \( M \) can be expressed as: \[ M^{-1} = \frac{1}{\text{det}(M)} \text{adj}(M) \] Therefore, substituting the determinant value: \[ M^{-1} = \frac{1}{4} \text{adj}(M) \] 3. **Using the Formula for Adjoint of Adjoint:** For any square matrix \( M \), the adjoint of the adjoint can be given by: \[ \text{adj}(\text{adj}(M)) = \text{det}(M)^{n-2} M \] where \( n \) is the order of the matrix. Since \( M \) is \( 3 \times 3 \): \[ \text{adj}(\text{adj}(M)) = \text{det}(M)^{3-2} M = \text{det}(M) \cdot M = 4M \] 4. **Substituting into the Given Equation:** Now we substitute \( M^{-1} \) and \( \text{adj}(\text{adj}(M)) \) into the equation: \[ M^{-1} \text{adj}(\text{adj}(M)) = \left(\frac{1}{4} \text{adj}(M)\right)(4M) \] Simplifying this gives: \[ M^{-1} \text{adj}(\text{adj}(M)) = \text{adj}(M) M \] 5. **Using the Property of Adjoint:** We know that: \[ \text{adj}(M) M = \text{det}(M) I \] Thus: \[ \text{adj}(M) M = 4I \] 6. **Equating to Find \( k \):** Now we have: \[ k^2 I = 4I \] This implies: \[ k^2 = 4 \] 7. **Finding the Values of \( k \):** Taking the square root of both sides gives: \[ k = \pm 2 \] ### Final Answer: The value of \( k \) may be \( 2 \) or \( -2 \).
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