Which of the following solutions has the highest normality?

Options

A. 172 milli equivalents in 200 ml
B. 84 milli equivalent in 100 ml
C. 275 milli equivalents in 250 ml
D. 43 milli equivalents in 60 ml

Explanation

To determine which solution has the highest normality, we need to calculate the normality for each option provided. Normality (N) is defined as the number of equivalents of solute per liter of solution. In this case, we will use the formula:

\[ N = \frac{\text{Number of equivalents}}{\text{Volume in liters}} \]

For convenience, we can also express normality in terms of milliequivalents and milliliters:

\[ N = \frac{\text{Number of milliequivalents}}{\text{Volume in milliliters}} \]

Now, let's calculate the normality for each option:

### Step 1: Calculate Normality for Option A
Given:
- Milliequivalents = 172
- Volume = 200 mL

\[ N_A = \frac{172 \text{ milliequivalents}}{200 \text{ mL}} = 0.86 \text{ N} \]

### Step 2: Calculate Normality for Option B
Given:
- Milliequivalents = 84
- Volume = 100 mL

\[ N_B = \frac{84 \text{ milliequivalents}}{100 \text{ mL}} = 0.84 \text{ N} \]

### Step 3: Calculate Normality for Option C
Given:
- Milliequivalents = 275
- Volume = 250 mL

\[ N_C = \frac{275 \text{ milliequivalents}}{250 \text{ mL}} = 1.1 \text{ N} \]

### Step 4: Calculate Normality for Option D
Given:
- Milliequivalents = 43
- Volume = 60 mL

\[ N_D = \frac{43 \text{ milliequivalents}}{60 \text{ mL}} \approx 0.716 \text{ N} \]

### Step 5: Compare Normalities
Now, we compare the normalities calculated:

- Normality of A = 0.86 N
- Normality of B = 0.84 N
- Normality of C = 1.1 N
- Normality of D = 0.716 N

### Conclusion
The solution with the highest normality is Option C, which has a normality of 1.1 N.

### Final Answer
**Option C has the highest normality.**

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