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25 g of MCl(4) contains 0.5 mole chlorin...

25 g of `MCl_(4)` contains 0.5 mole chlorine then its gram molecular weight is

A

`"100 g mol"^(-1)`

B

`"200 g mol"^(-1)`

C

`"150 g mol"^(-1)`

D

`"400 g mol"^(-1)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the gram molecular weight (molar mass) of MCl₄ given that 25 g of MCl₄ contains 0.5 moles of chlorine, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the relationship between moles of chlorine and moles of MCl₄**: - In one mole of MCl₄, there are 4 moles of chlorine (Cl). - Therefore, the relationship is: \[ 1 \text{ mole of MCl}_4 \rightarrow 4 \text{ moles of Cl} \] 2. **Determine the moles of MCl₄ corresponding to the given moles of chlorine**: - Since we have 0.5 moles of chlorine, we can find the moles of MCl₄ that would produce this amount of chlorine: \[ \text{Moles of MCl}_4 = \frac{0.5 \text{ moles of Cl}}{4} = 0.125 \text{ moles of MCl}_4 \] 3. **Use the mass of MCl₄ to find its molar mass**: - We know that the mass of MCl₄ is given as 25 g. We can use the formula for molar mass: \[ \text{Molar Mass} = \frac{\text{mass}}{\text{moles}} \] - Plugging in the values: \[ \text{Molar Mass of MCl}_4 = \frac{25 \text{ g}}{0.125 \text{ moles}} = 200 \text{ g/mol} \] 4. **Conclusion**: - The gram molecular weight (molar mass) of MCl₄ is 200 g/mol. ### Summary: The molar mass of MCl₄ is calculated to be 200 g/mol based on the given information.

To find the gram molecular weight (molar mass) of MCl₄ given that 25 g of MCl₄ contains 0.5 moles of chlorine, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the relationship between moles of chlorine and moles of MCl₄**: - In one mole of MCl₄, there are 4 moles of chlorine (Cl). - Therefore, the relationship is: \[ ...
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Knowledge Check

  • 25 g of MCl_(4) contains 0.5 mol chlorine then its molecular mass is:

    A
    100g `"mol"^(-1)`
    B
    200g `"mol"^(-1)`
    C
    `150g "mol"^(-1)`
    D
    `400g "mol"^(-1)`
  • A giant molecule contains 0.25% of a metal whose atomic weight is 59. Its molecular contains one atom of that metal. Its molecular weight : is -

    A
    5900
    B
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    C
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    D
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  • A compounds contains 69.5% oxygen and 30.5 % nitrogen and its molecular weight is 92. The formula of that compound is :-

    A
    `N_(2)O`
    B
    `NO_(2)`
    C
    `N_(2)O_(4)`
    D
    `N_(2)O_(5)`
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