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The frequency of the characterstic X ray...

The frequency of the characterstic X ray of `K_(alpha)` line of metal targent 'M' is `2500 cm^(-1)` and the graoh between `sqrt(v)` Vs 'z' is as follows, then atomic number of M is

A

49

B

50

C

51

D

25

Text Solution

Verified by Experts

The correct Answer is:
C
`sqrt(v)=a(Z-b) " " sqrt(v)=aZ-ab`
`aZ = sqrt(v)+ab rarr Z = (sqrt(v))/(a)+b " " therefore y=mx + c`
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Knowledge Check

  • The characteristic X-rays for the lines of K_(a) series in element X and Y are 9.87 Å and 14.6 Å respectively .If Moseley's equation sqrt(v) = 4.9 xx 10^(7) (Z - 0.75) is followed: The atomic number of X is

    A
    8
    B
    10
    C
    12
    D
    16

  • The characteristic X-rays for the lines of K_(a) series in element X and Y are 9.87 Å and 14.6 Å respectively .If Moseley's equation sqrt(v) = 4.9 xx 10^(7) (Z - 0.75) is followed: The atomic number of Y is

    A
    10
    B
    6
    C
    8
    D
    12

  • What is atomic number Z when v= 2500s^(-1) and value of a=1 amd b=1.

    A
    50
    B
    40
    C
    51
    D
    53
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