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Which of the following does not have sp^...

Which of the following does not have `sp^3` hybridisation ?

A

`BF_4^(-)`

B

`H_3O^(+)`

C

`OF_2`

D

`BF_3`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given compounds does not have `sp^3` hybridization, we will analyze each option step by step. ### Step 1: Analyze BF4⁻ - **Valence Electrons**: Boron (B) has 3 valence electrons, and each Fluorine (F) has 7 valence electrons. In BF4⁻, Boron forms 3 bonds with Fluorine and accepts a lone pair from an F⁻ ion. - **Steric Number Calculation**: - Number of sigma bonds = 4 (3 from F and 1 from the coordinate bond) - Number of lone pairs = 0 - Steric number = 4 + 0 = 4 - **Hybridization**: Since the steric number is 4, the hybridization is `sp^3`. ### Step 2: Analyze H3O⁺ - **Valence Electrons**: Oxygen (O) has 6 valence electrons. In H3O⁺, it forms 3 bonds with Hydrogen (H) and has one lone pair. - **Steric Number Calculation**: - Number of sigma bonds = 3 - Number of lone pairs = 1 - Steric number = 3 + 1 = 4 - **Hybridization**: Since the steric number is 4, the hybridization is `sp^3`. ### Step 3: Analyze OF2 - **Valence Electrons**: Oxygen (O) has 6 valence electrons. In OF2, it forms 2 bonds with Fluorine and has 2 lone pairs. - **Steric Number Calculation**: - Number of sigma bonds = 2 - Number of lone pairs = 2 - Steric number = 2 + 2 = 4 - **Hybridization**: Since the steric number is 4, the hybridization is `sp^3`. ### Step 4: Analyze BF3 - **Valence Electrons**: Boron (B) has 3 valence electrons. In BF3, it forms 3 bonds with Fluorine and has no lone pairs. - **Steric Number Calculation**: - Number of sigma bonds = 3 - Number of lone pairs = 0 - Steric number = 3 + 0 = 3 - **Hybridization**: Since the steric number is 3, the hybridization is `sp^2`. ### Conclusion Among the given options, **BF3** does not have `sp^3` hybridization. ### Summary of Steps: 1. Analyze the valence electrons and bonding in each compound. 2. Calculate the steric number using the formula: Steric number = Number of sigma bonds + Number of lone pairs. 3. Determine the hybridization based on the steric number.
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