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In the Cannizzaro reaction given below: ...

In the Cannizzaro reaction given below:
`2Ph-CHO overset(overset(Θ)OH)rarrPh-CH_(2)OH+PhCO_(2)^(-)` the slowest step is:

A

the attack of `OH^(-)` at the carbonly group

B

the transfer of hydride to the carbonyl froup

C

the abstraction of proton from the carboxylic acid

D

the deprotonation of `Ph-CH_(2)OH`

Text Solution

Verified by Experts

The correct Answer is:
B

`Ph-overset(O)overset(||)(C)-OH+H^(-)`
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Knowledge Check

  • In the cannizzaro reaction given below, 2Ph-CHO overset(OH^(-))to Ph-CH_(2)OH+PhCO_(2)^(-) the slowest step is

    A
    the attach of `.^(-)OH` at the carbonyl group
    B
    the transfer of hydride ion to the carbonyl group
    C
    the abstraction of a proton from the carboxylic acid
    D
    the deprotonation of `Ph-CH_(2)OH`.

  • In the Cannizzaro reaction given below 2Ph- CHO overset(OH^(-))to Ph- CH_2OH + PhCO_2^(-) the slowest step is

    A
    the attack of OH at the carbonyl group.
    B
    the transfer of hydride to the carbonyl group.
    C
    the abstraction of proton from the carboxylic acid.
    D
    the deprotonation of `Ph-CH_2OH`

  • In Cannizaro reaction given below: 2Ph-CHOoverset(0H^(ϴ))(to)PhCH_(2)OH+PhCO_(2)^(O) the slowest step is:

    A
    The transfer of hydride to carbonyl group
    B
    The abstractiion of protons the carboxylic group
    C
    The deprotonation of `PhCH_(2)OH`
    D
    The attack of `OH^(ϴ)` at the carboxyly group

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