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A can do a piece of work in 20 days whil...

A can do a piece of work in 20 days while B can do it in 30 days. Both of them start the work together and work for some time, then B leaves. If A completes the remaining work in 10 days, then find the number of days for which they worked together.

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To solve the problem step by step, we will calculate the amount of work done by A and B, and then determine how long they worked together before B left. ### Step 1: Calculate the work rates of A and B - A can complete the work in 20 days, so A's work rate is: \[ \text{Work rate of A} = \frac{1}{20} \text{ (work per day)} \] - B can complete the work in 30 days, so B's work rate is: \[ \text{Work rate of B} = \frac{1}{30} \text{ (work per day)} \] ### Step 2: Calculate the combined work rate of A and B - When A and B work together, their combined work rate is: \[ \text{Combined work rate} = \frac{1}{20} + \frac{1}{30} \] - To add these fractions, find a common denominator. The least common multiple of 20 and 30 is 60: \[ \frac{1}{20} = \frac{3}{60}, \quad \frac{1}{30} = \frac{2}{60} \] - Therefore, the combined work rate is: \[ \text{Combined work rate} = \frac{3}{60} + \frac{2}{60} = \frac{5}{60} = \frac{1}{12} \text{ (work per day)} \] ### Step 3: Determine the total work done by A in 10 days - A completes the remaining work in 10 days. Since A's work rate is \(\frac{1}{20}\), the amount of work A does in 10 days is: \[ \text{Work done by A in 10 days} = 10 \times \frac{1}{20} = \frac{10}{20} = \frac{1}{2} \text{ of the total work} \] ### Step 4: Calculate the total work - If A completed \(\frac{1}{2}\) of the total work in 10 days, then the total work can be represented as: \[ \text{Total work} = 1 \text{ (whole work)} \] ### Step 5: Determine the work done before B leaves - Since A completed \(\frac{1}{2}\) of the work alone, the other half must have been completed by A and B together. Thus, the work done by A and B together is: \[ \text{Work done by A and B together} = 1 - \frac{1}{2} = \frac{1}{2} \] ### Step 6: Calculate the time they worked together - Let \(T\) be the number of days they worked together. The work done by A and B together in \(T\) days is: \[ T \times \frac{1}{12} = \frac{1}{2} \] - Solving for \(T\): \[ T = \frac{1/2}{1/12} = \frac{1}{2} \times \frac{12}{1} = 6 \text{ days} \] ### Final Answer - A and B worked together for **6 days**. ---
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