Home
Class 12
CHEMISTRY
A piece of wood was found to have ""^(14...

A piece of wood was found to have `""^(14)C//^(12)C` ratio 0.7 times that in a living plant. Calculate the period (in years) when the plant died. (`t_((1)/(2)) " for " C^(14)= 5760yr`)

A

2770 yr

B

2966 yr

C

2980 yr

D

3070 yr

Text Solution

Verified by Experts

The correct Answer is:
B

Given, `N_(0) = 1N, N_(t) = 0.70 and t_(1//2) = 57600 yr`
`k = (0.693)/(t_(1//2)) = (0.693)(5760)`
We also know, `k = (2.303)(t) "log" (N_(0))/(N_(t)) = (0.693)/(5760)`
or `t = (2.303 xx 5760 xx 0.155)/(0.693) = 2966yr`
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    ERRORLESS |Exercise Ordinary Thinking (Artificial transmutation )|59 Videos
  • NUCLEAR CHEMISTRY

    ERRORLESS |Exercise Ordinary Thinking (Isotopes-Isotones and Nuclear isomers)|34 Videos
  • NUCLEAR CHEMISTRY

    ERRORLESS |Exercise Ordinary Thinking (Causes of radioactivity and Group displacement law)|66 Videos
  • NITROGEN CONTAINING COMPOUNDS

    ERRORLESS |Exercise JEE (ADVANCED) 2018 MORE THAN ONE CHOICE CORRECT ANSWER|1 Videos
  • ORES, MINERALS AND METALLURGICAL EXTRACTION

    ERRORLESS |Exercise JEE ANSWER TPYE QUESTION (JEE Advanced) 2018) Numeric answer type question|1 Videos

Similar Questions

Explore conceptually related problems

A piece of wood was found to have C^(14)//C^(12) ratio 0.6 times that in a living plant. Calculate that in a living plant. Calculate the period when the plant died. (Half life of C^(14) = 5760 years)?

A piece of wood is found to have the (C^(14))/(C^(12)) ratio to be 0.5 times of that in a living plant The number of years back the plant died will be ( T of C^(14)=5,580 years)

A piece of charcoal from the ruins of a settlement in Japan was found to have .^(14)C// .^(14)C ratio what was 0.617 times that found in living organisms. How old is the piece of charcol? ( t_(1//2) for .^(14)C is 5770 year?)

The C-14 content of an ancient piece of wood was found to have three tenths of that in living trees. How old is that piece of wood? (log 3= 0.4771, log 7 = 0.8540 , Half-life of C-14 = 5730 years )

ERRORLESS -NUCLEAR CHEMISTRY -Ordinary Thinking (Rate of decay and Half - life)
  1. A radioactive element gets spilled over the floor of a room. Its half-...

    Text Solution

    |

  2. A radioactive element has a half life of one day. After three days the...

    Text Solution

    |

  3. A piece of wood was found to have ""^(14)C//^(12)C ratio 0.7 times tha...

    Text Solution

    |

  4. If the half-life period of a first order reaction is 138.6 min, then t...

    Text Solution

    |

  5. The disintegration constant of radium with half-life 1600 yr is

    Text Solution

    |

  6. 10g of a radioactive substance is reduced to 1.25 g after 15 days. Its...

    Text Solution

    |

  7. If the half of an isotope X is 10 years , its decay contant is

    Text Solution

    |

  8. A radioactive isotope has a half-life of 27 days. Starting with 4g of ...

    Text Solution

    |

  9. 8g of the radioactive isotope, cesium -137 were collected on February ...

    Text Solution

    |

  10. A radioactive isotope decays to such a rate that after 96 min only 1/8...

    Text Solution

    |

  11. The half-life period t(1//2) of a radioactive element is N years. The ...

    Text Solution

    |

  12. If the disintegration constant is 6.93 xx 10^(-6) yr^(-1), then half-l...

    Text Solution

    |

  13. In the case of a radioisotope , the value of t(1//2) and lambda are id...

    Text Solution

    |

  14. 2 g of a radioactive sample having half-life of 15 days was synthesise...

    Text Solution

    |

  15. If n(t) number of radioatoms are present at time t, the following expr...

    Text Solution

    |

  16. The half-life for decay of .^(14)C " by " beta-emission is 5730 years....

    Text Solution

    |

  17. Rate constant for a reaction is lambda. Average life is representative...

    Text Solution

    |

  18. In which radiation mass number and atomic number will not change ?

    Text Solution

    |

  19. t(1//2) of C^(14) isotope is 5770 years. time after which 72% of isot...

    Text Solution

    |

  20. A radioactive substance takes 20 min to decay 25%. How much time will ...

    Text Solution

    |