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Factorize 2x^2-7x-39....

Factorize ` 2x^2-7x-39`.

Text Solution

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The given expression is `2x^2-7x-39`.
Here, `2xx (-39) =-78`
So, we split -7 into two parts whose sum is -7 and product `-78`.
Clearly, `(-13)+6=-7 and (-13)xx6=-78`
`therefore 2x^2-7x-39 =2x^2- 13x +6x-39`
` =x(2x-13)(x+3)`
Hence, `(2x^2-7x-39)=(2x-13)(x+3)`.
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