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9x^2+12xy...

`9x^2+12xy`

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To factor the expression \(9x^2 + 12xy\), we can follow these steps: ### Step 1: Identify the common factors Look at the coefficients and the variables in both terms: - The coefficients are 9 and 12. - The variable part includes \(x^2\) and \(xy\). ### Step 2: Find the greatest common factor (GCF) The GCF of the coefficients 9 and 12 is 3. For the variable part, the common factor is \(x\) (since both terms have at least one \(x\)). ### Step 3: Factor out the GCF Now, we can factor out \(3x\) from both terms: \[ 9x^2 + 12xy = 3x(3x) + 3x(4y) \] ### Step 4: Write the factored form After factoring out \(3x\), we can rewrite the expression as: \[ 9x^2 + 12xy = 3x(3x + 4y) \] ### Final Answer Thus, the factored form of \(9x^2 + 12xy\) is: \[ 3x(3x + 4y) \] ---
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Knowledge Check

  • Write the numerical coefficients of the followings . 17x^2y 12xy^3 3/5x -3/2x^2

    A
    `17x^(2)y`
    B
    `12xy^(3)`
    C
    `(3)/(5)x`
    D
    `(-3)/(2)x^(2)`
  • Solve (9x^(2) + 8xy-4)-(7x^(2) -2xy +2) .

    A
    `2x^(2)+ 10xy-6`
    B
    `2x^(2) -10xy -8`
    C
    `2x^(2) + 10xy - 8`
    D
    `2x^(2) -10xy + 6`
  • If cos^(-1)((x)/(3))+cos^(-1)((y)/(2))=(theta)/(2) , then the value of 4x^(2)-12xy cos((theta)/(2))+9y^(2) is equal to :

    A
    `18(1+cos theta)`
    B
    `18(1-cos theta)`
    C
    `36(1+cos theta)`
    D
    `36(1-cos theta)`
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