9 x^2 -16 y^2...

`9 x^2 -16 y^2`

Text Solution

Verified by Experts

The correct Answer is:

`(3x-4y)(3x+4y)`

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The latus rectum of the hyperbola 9x ^(2) -16 y^(2) + 72x - 32y-16=0 is

Find the centre, eccentrcity, foci and directrices of the hyperboal : 9x^(2) - 16y^(2) + 18x + 32y - 151 = 0 .

Knowledge Check

The coordinates of the foci for the hyperbola 9x^(2) - 16y^(2) = 144 are

A

(5.0 ) and(-5,0)

B

(2,0)and(-2,0)

C

(4,0) and (-4, 0)

D

(1,0) and (-1,0)

Find the eccentricity for the hyperbola 9x^(2) - 16y^(2) = 144

A

`5/4`

B

`3/4`

C

`7/4`

D

`1/4`

A common tangent to 9x^(2) - 16y^(2) = 144 and x^(2) + y^(2) = 9 is

A

`y sqrt(7) = sqrt(2)x + 15`

B

`ysqrt(7) = 3sqrt(2)x + 15`

C

`y = 3sqrt(2)x + 15`

D

`ysqrt(7) = 3x + 15`

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Find the centre, eccentricity and foci of the hyperbola, 9x^2 - 16y^2 - 18x - 64y-199 = 0

Find the length of the transverse axis, conjugate axis, eccentricity, vertices, foci and directrices of the hyperbola 9x^2 - 16y^2 = 144 .

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The difference of the focal distance of any point on the hyperbola 9x ^(2) -16 y ^(2) =144, is

STATEMENT-1 : The line 3x + 4y = 5 intersects the hyperbola 9x^(2) - 16y^(2) = 144 only at one point. and STATEMENT-2 : Given line is parallel to an asymptotes of the hyperbola.