Evaluate : `int(sinx)/(sin(x-alpha))dx`.

Explanation

To evaluate the integral \( \int \frac{\sin x}{\sin(x - \alpha)} \, dx \), we can follow these steps:

### Step 1: Rewrite the integrand
We start by rewriting the integrand. We can express \( \sin x \) as \( \sin(x - \alpha + \alpha) \):
\[ \sin x = \sin((x - \alpha) + \alpha) = \sin(x - \alpha) \cos \alpha + \cos(x - \alpha) \sin \alpha \]
Thus, we can rewrite the integral:
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