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Calculate enthalpy change of the followi...

Calculate enthalpy change of the following reaction :
`CH_(2) = CH_(2)(g) + H_(2)(g) rarr CH_(3) - CH_(3)(g)`
The bond energy of C - H, C - C, C = C, H - H are `414,347, 615 and 436 kJ` `mol^(-1)` respectively.

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To calculate the enthalpy change (ΔH) for the reaction: \[ \text{CH}_2 = \text{CH}_2(g) + \text{H}_2(g) \rightarrow \text{CH}_3 - \text{CH}_3(g) \] we will use the bond energies provided for the relevant bonds involved in the reaction. ### Step-by-Step Solution: ...
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