Discuss the reductive ozonloysis product of the following compound
`CH_(2)=CH-underset(H_(3)C)underset(|)(C )=underset(CH_(3))underset(|)(C )-CH=CH_(2)` ,

Explanation

To discuss the reductive ozonolysis products of the compound `CH2=CH-(CH3)(C)-CH=CH2`, we will follow these steps:

### Step 1: Identify the Structure
First, we need to draw the structure of the given compound. The compound has two double bonds and substituents on the carbon chain.

### Step 2: Understand Reductive Ozonolysis
In reductive ozonolysis, the double bonds in the compound will break, and ozone (O3) will react with the compound. The reaction is followed by a reduction step, typically using zinc (Zn) or another reducing agent, which leads to the formation of carbonyl compounds.

### Step 3: Break the Double Bonds
The compound has two double bonds:
1. Between the first two carbon atoms (C1=C2).
2. Between the last two carbon atoms (C4=C5).

During reductive ozonolysis, these double bonds will break and will be converted into carbonyl groups (C=O).

### Step 4: Identify the Products
1. **From the first double bond (C1=C2)**:
- This will yield a carbonyl compound (aldehyde or ketone) on both sides of the broken bond.
- The product will be `CH2=O` (formaldehyde) from one side and `C(CH3)=O` (acetone) from the other side.

2. **From the second double bond (C4=C5)**:
- This will also yield carbonyl compounds.
- The product will be `CH2=O` (formaldehyde) from one side and `C(CH3)=O` (acetone) from the other side.

### Step 5: List the Final Products
The final products from the reductive ozonolysis of the compound are:
1. **Formaldehyde (HCHO)**
2. **Acetone (C3H6O)**
3. **Another molecule of formaldehyde (HCHO)**
4. **Another molecule of acetone (C3H6O)**

### Summary of Products
Thus, the products of the reductive ozonolysis of the compound are:
- 2 molecules of formaldehyde (HCHO)
- 2 molecules of acetone (C3H6O)