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In terms of Rydberg constant R, the shor...

In terms of Rydberg constant `R`, the shortest wavelength in the Balmer series of the hydrogen , atom spestrum will have wavelength

A

`(R )/(4)`

B

`(36R)/(5)`

C

`(5)/(36R)`

D

`(4)/(R )`

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • The shortest wavelength in the balmer series is (R=1.097xx10^7m^-1)

    A
    200 nm
    B
    256.8 nm
    C
    300 nm
    D
    364.6 nm