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How does the degree of ionization (assum...

How does the degree of ionization (assuming lt lt 1)` of a weak electroyte vary with concentration ? Give exact relationship.

Text Solution

Verified by Experts

`alpha=sqrt(K_(i)//C)`. It is called Ostwald's dilution law (`K_(i)` is ionization constant and C is molar concentration of the eletrolyte).
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Knowledge Check

  • If alpha is the degree of ionization, C the concentration of a weak electrolyte and K_(a) the acid ionization constant , then the correct relationship between alpha and C is

    A
    `alpha^(2) = sqrt(K_(a)/C)`
    B
    `alpha^(2) = sqrt(C/K_(a))`
    C
    `alpha= sqrt(K_(a)/C)`
    D
    `alpha = sqrt(C/K_(a))`
  • If alpha is the degree of ionization, C the concenr=tration of a weak electrolyte and K_(a) the acid ionization constant, then the correct relationship between alpha , C and K_(a) is

    A
    `alpha^(2) = sqrt((K_(a))/(C))`
    B
    `alpha^(2) = sqrt((C)/(K_(a))`
    C
    `alpha = sqrt((K_(a))/(C))`
    D
    `alpha = sqrt((C)/(K_(a))`
  • If C the concentration of a weak electrolyte , alpha is the degree of ionization and K_a is the acid ionization constant , then the correct relationship between alpha , C and K_a is

    A
    `a^2=sqrt((K_a)/C)`
    B
    `a^2=sqrt((C)/(K_a))`
    C
    `alpha = sqrt((C)/(K_a))`
    D
    `alpha = sqrt ((K_a)/(C))`
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