Home
Class 11
MATHS
Find the equation of the set of points w...

Find the equation of the set of points which are equidistant from the points `(1, 2, 3)`and `(3, 2, 1)`.

Text Solution

AI Generated Solution

To find the equation of the set of points that are equidistant from the points \( A(1, 2, 3) \) and \( B(3, 2, 1) \), we can follow these steps: ### Step 1: Define the points and the variable point Let \( P(x, y, z) \) be any point in space that is equidistant from points \( A(1, 2, 3) \) and \( B(3, 2, 1) \). ### Step 2: Set up the distance equations The distance from point \( P \) to point \( A \) is given by the distance formula: \[ ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • INTRODUCTION TO THREE DIMENSIONAL GEOMETRY

    NCERT|Exercise SOLVED EXAMPLES|13 Videos
  • INTRODUCTION TO THREE DIMENSIONAL GEOMETRY

    NCERT|Exercise MISCELLANEOUS EXERCISE|6 Videos
  • INTRODUCTION TO THREE DIMENSIONAL GEOMETRY

    NCERT|Exercise EXERCISE 12.1|4 Videos
  • CONIC SECTIONS

    NCERT|Exercise EXERCISE 11.1|15 Videos
  • LIMITS AND DERIVATIVES

    NCERT|Exercise EXERCISE 13.3|8 Videos

Similar Questions

Explore conceptually related problems

The equation of the locus of points which are equidistant from the points (2,-3) and (3,-2) is

The equation of the set of points which are equidistant the points (1,-2,3) and (3,-2,-1) is ……….

Knowledge Check

  • The equation of the set of all points which are equidistant from the point (0, 4) and the line y = -4

    A
    `x^(2) = 16y`
    B
    `x^(2) =-16y`
    C
    `y^(2) =16x`
    D
    `y^(2) = -16x`
  • Similar Questions

    Explore conceptually related problems

    Find the locus of the points which are equidistant from the points (1,2,3) and (3,2,11).

    Find the locus of a point which is equidistant from the points (-1,2,3) and (3,2,1)

    Find the equation of the set of all points which are equidistant from the points (a^2 + b^2 , a^2 - b^2) and (a^2 - b^2 , a^2 + b^2)

    Find the equation of the locus of the point P equidistant from the points (2,3),(1,4)

    Find the equation of the locus of the point "P" equidistant from the points (-3,2),(0,4)

    Find the equation of the locus of the point P equidistant from the points (-3,2),(0,4)

    The equation of the locus of points which are equidistant from the points (2,-3) and (3,-2) is (A) x+y=0 (B) x+y=7 (C) 4x+4y=38 (D) x+y=1