Numbers play an important role in our life. We use numbers in our day to day life to count things.
While counting we use numbers to represent any quantity, to measure any distance or length.
The counting numbers starting from 1,2,3,4,5 are termed as natural numbers.
The set of counting numbers and zero are known as whole numbers.
Whole numbers are 0,1,2,3,4,5,6,7, and so, on
The symbols used by different civilizations to represent numbers are as below:
Symbols
One
Two
Three
Four
Five
Six
Seven
Eight
Nine
Ten
Indo-Arabic
1
2
3
4
5
6
7
8
9
10
Dev Nagri
१
२
३
४
५
६
७
८
९
१०
Arabs
١
٢
٣
٤
٥
٦
٧
٨
٩
١٠
Roman
I
II
III
IV
V
VI
VII
VIII
IX
X
Even Natural Numbers: Numbers which are divisible by 2 are called even numbers, e.g. 2,4,6,8,10, ....
Odd Natural Numbers: Numbers which are not divisible by 2 are called odd numbers, e.g. 1,3,5,7,9,….
If at unit place, we have 0,2,4,6,8 then number is even otherwise it is odd.
2.0Comparing and Building Numbers
To put large numbers in order, you must check the number of digits in them first. If the number of digits vary in each number, the smallest number is the one which is having the least number of digits and the greatest number is the one which is having the maximum number of digits.
Comparing Numbers with the Same Number of Digits
Comparison of the numbers with the same number of digits starts from the left-hand side.
You must compare the face values of the digits having the same place value in the numbers until you come across unequal digits.
0 is the smallest whole number and largest whole number cannot be define because
whole number goes to infinite.
Building numbers
Now, you will learn to build numbers, under different conditions.
Greatest 4-digit number is 9999 and greatest 5-digit number is 99999 .
3.0Introducing 6-Digit, 7-Digit and 8-Digit Numbers
Till now you have learnt up to 5 digit numbers and you know that the greatest 5 digit number is 99,999 . On adding 1 to it, we get the smallest 6-digit number.
99999+1=1,00,000, read as one lakh.
The largest 6-digit number is 9,99,999. On adding 1 to it, we get the smallest 7 -digit number.
9,99,999+1=10,00,000, read as ten lakh.
The largest 7 -digit number is 99,99,999. On adding 1 to it, we get the smallest 8 -digit number.
99,99,999+1=1,00,00,000, read as one crore.
Ascending Order
When the numbers are arranged from the smallest to the largest number, those numbers are said to be in an ascending order. The numbers are arranged from left to right in increasing order.
Descending Order
When the numbers are arranged from the largest to the smallest number, those numbers are said to be in descending order. The numbers are arranged from left to right in decreasing order.
Ascending order is represented by < (less than) symbol, whereas descending order is represented by > (greater than) symbol.
Shifting Digits
Changing the position of digits in a number, changes magnitude of the number.
Example:
Take a number 257.
The condition here is to exchange its hundreds and unit digit and form the new number.
That is, exchange 2 to 7 and 7 to 2 .
Here comes a question.
Which is greater and which is least among the numbers?
To find that express the numbers formed in both ascending and descending order.
The number before shifting is 257 . Exchanging the hundreds and the unit digits, the number after shifting is 752 .
That is, if we exchange the hundreds and unit digit, the resultant number becomes greater.
4.0Place Value and Face Value
Every digit has two values the place value and the face value. The face value of a digit does not change while its place value changes according to its position and number.
The face value of a digit in a numeral is its own value, at whatever place it may be.
Place value or local value of a digit in a given number is the value of the digit because of the place or position of the digit in the number.
Expanded Form of A Number
If we express a given number as the sum of its place values, it is called its expanded form.
5.0Indian and International System of Numeration
Suppose a newspaper report state that Rs. 2500 crore has been allotted by the government for National Highway construction. The same amount of Rs. 2500 crore is sometimes expressed as 25 billion. In the Indian system, we express it as Rs. 2500 crore and in the International system, the same number is expressed as 25 billion. Hence, you need to understand both the systems and their relationship.
Indian System of Numeration
The Indian system of numeration or Hindu-Arabic numeral system is a positional decimal numeral system developed between the 1st and 5th centuries by Indian mathematicians, adopted by Persian and Arabian mathematicians and spread to the western world by the High Middle Ages. It uses ten basic symbols 0,1,2,3,4,5, 6,7,8,9 (called digits) and the idea of place value.
For a given numeral, we start from the extreme right as :
Ones, Tens, Hundreds, Thousands, Ten Thousands, Lakhs, Ten Lakhs, etc. Each place represents ten times the one which is immediately to its right.
Indian system of numbers
Crores
Lakhs
Thousands
Ones
Ten Crore
One Crore
Ten Lakh
One Lakh
Ten Thousand
One Thousand
One Hundred
Ten
One
₹10,00,00,000 9 Digits
₹1,00,00,000 8 Digits
₹10,00,000 7 Digits
₹1,00,000 6 Digits
₹10,000 5 Digits
₹1,000 4 Digits
₹100 3 Digits
₹10 2 Digits
₹1 1 Digit
Indian place-value chart
Crores
Lakhs
Thousands
Ones
TC
C
TL
L
TTh
Th
H
T
0
1
0
0
0
0
0
0
0
1C=1 crore =1,00,00,000
International System of Numeration
International system of numeration is adopted by all the countries throughout the world.
International system of numbers
Millions
Thousands
Ones
Hundred Million
Ten Million
One Million
Hundred Thousand
Ten Thousand
One Thousand
One Hundred
Ten
One
100,000,000
10,000,000
1,000,000
100,000
10,000
1,000
100
10
1
9 Digits
8 Digits
7 Digits
6 Digits
5 Digits
4 Digits
3 Digits
2 Digits
1 Digit
International place-value chart
Millions
Thousands
Ones
HM
TM
M
HTh
TTh
Th
H
T
0
1
0
0
0
0
0
0
0
1TM=10 million =10,000,000
6.0Use of Commas
Commas help us in reading and writing large numbers. In our Indian system of numeration, commas are used to mark thousands, lakhs and crores. The first comma comes after hundreds place and marks thousands. The second comma comes after ten thousands place and marks lakh. The third comma comes after ten lakh place and marks crore.
In International system of numeration, commas are used to mark thousands and millions. It comes after every three digits from the right.
Express 643871 in both the systems of numeration.
Explanation
Indian: 6,43,871
Six lakh forty three thousand eight hundred and seventy one
Roman numbers were invented for the purpose of counting and performing other day-today transactions.
7.0Roman Numerals
The Roman numerals is the numeral system of ancient Rome. It uses combinations of letters from the Latin alphabet to signify values. The numbers 1 to 10 can be expressed in Roman numerals as follows:
I, II, III, IV, V, VI, VII, VIII, IX, and X.
This followed by XI for 11, XII for 12, ... till XX for 20. Some more roman numerals are :
I
V
X
L
C
D
M
1
5
10
50
100
500
1000
The Roman numeral system is decimal but not directly positional and does not include a zero.
Rules to form Roman numerals
We can form different roman numerals using the symbols and the following rules.
Rule 1: If a symbol is repeated one after the other, its value is added as many times as it occurs. For example,
III=1+1+1=3XX=10+10=20
Rule 2 : The symbols I, X, C and M can be repeated up to a maximum of three times.
For example,
I=1,II=2,III=3X=10,XX=20,XXX=30C=100,CC=200,CCC=300M=1000,MM=2000,MMM=3000
Rule 3: The symbols V, L and D (i.e., 5, 50, and 500, respectively) can never be repeated in a roman numeral.
Rule 4: If a symbol with a smaller value is written on the right of a symbol with a greater value, then its value is added to the value of the greater symbol. For example,
XII=10+2=12,LX=50+10=60,
DCCCX =500+300+10=810
Rule 5 : If a symbol with a smaller value is written on the left of a symbol with a larger value, then its value is subtracted from the value of the greater symbol. For example,
IV=5−1=4,IX=10−1=9,CD=500−100=400VI=5+1=6,XI=10+1=11,DC=500+100=600
Note: 'I' can be subtracted from V and X once only. X can be subtracted from L and C once only. C can be subtracted from D and M once only. Thus, I or V is never written to the left of L or C.L is never written to the left of C.
Zero is the only number that can't be represented in Roman numberals.
VC is not possible because V,L & D are never subtracted.
8.0Use of Brackets
Raju brought 6 pencils from the market, each at Rs. 2. His brother Ramu also bought 8 pencils of the same type. Raju and Ramu both calculated the total cost but in their own ways. Raju found that they both spent Rs. 28 and he used the following method:
(6×2)+(8×2)=(12+16)=28
Here number of operations are two times multiplication and one time addition
But Ramu found an easier way. He did 6+8=14 and then (2×14)=28. The use of brackets makes this sum easy. It can be done as follows :
Rs. 2×(6+8)= Rs. (2×14)
= Rs. 28
Here first solve the operation inside the bracket and then multiply it by the number outside.
Now number of operations are one addition and one multiplication.
So, second method takes less time.
9.0BODMAS Explanation
B→ Brackets first (parentheses)
0→Of
DM → Division and Multiplication (start from left to right)
AS → Addition and Subtraction (start from left to right)
Note:
(i) Start Divide/Multiply from left side to right side since they perform equally.
(ii) Start Add/Subtract from left side to right side since they perform equally.
10.0Rounding Numbers
Rounding involves replacing one number with another number that's easier to work with. Rounded numbers can be easier to use.
Suppose you want to find 18×43, but had lost the calculator. You could find an answer close to 18×43 by rounding to the nearest ten.
"Rounding to the nearest ten" means replacing a number with the nearest multiple of 10 .
Replacing a number with a higher number is called rounding up.
Replacing a number with a lower number is called rounding down.
Procedure of Round to Different Place Values
You can round numbers to place values other than tens.
Write the number. Underline the digit in the position you want to round to.
If the digit to the right of the underlined digit is 5 or more, round up.
If the digit to the right of the underlined digit is 4 or less, round down.
Note: When we round a number to nearest place, all other digits to the right of the place becomes zero. Ex round 24912 to nearest hundred, we will get 24900 . Digits to the right of 9 become zero.
While converting 27381 into nearest thousands, we will focus on the digit which is on hundred place.
Using Rounded Numbers
Now, you will learn more about using rounded numbers. You'll think about how much certain numbers should be rounded. You'll also see how rounded numbers are useful for checking your work. People round numbers to different place values depending on what the numbers are being used for.
The amount of rounding affects the accuracy
If you use rounding to estimate a sum, be careful how much you round.
Rounding to higher place values usually gives an estimate farther from the actual answer than rounding to lower place values.
Rounded numbers can be used to check work
Many times you'll want to check your work without doing the calculation all over again.
Rounding is a way to see if your answer is reasonable.
Note: Using rounded numbers to check your answer won't ever tell you that your answer is definitely right, only whether it is reasonable. Your answer might be close to the real answer but could still be wrong.
11.0Estimation
Estimation means "making a good guess." We can use it if we don't need to know an exact answer, or if a question has no exact right answer.
You can estimate when there's no exact answer
Sometimes in math there is no exact right answer.
You can use the information you do have to make an estimate.
Using Estimation
Estimation is really useful in a lot of real-life situations, where you might not be able, or don't need, to do an exact calculation.
There are other times when it's better to figure out the exact answer.
Estimates aren't always a good idea
There are some situations where you definitely shouldn't use an estimate.
12.0Use of Numbers in Everyday Life
Numbers are used immensely in our everyday life, such as measuring the length of a small object as pencil, the distance between two given places, the weight of an orange, the weight of a ship, the amount of juice in a glass and the amount of water in a lake.
Small lengths are measured in millimeter ( mm ) and centimeter ( cm ) while bigger lengths are measured in meter ( m ) and kilometer ( km ).
Meter ( m ) is the standard unit of length and we define it as :
1m=100cm=1000mm∴1cm=10mm∴100cm=100×10=1000mm1km=1000m
Also, 1km=(1000×1000)mm=1000000mm
Similarly, the units of weight are as under:
1g=1000mg1kg=1000gm1kg=(1000×1000)mg=1000000mg
For capacity or volume,
1ℓ=1000mL and 1kℓ=1000ℓ1kℓ=1000×1000mℓ=1000000mℓ
For Distance
km
hm
dam
m
dm
cm
mm
For Weight
kg
hg
dag
g
dg
cg
mg
For Liquids
kl
hl
dal
l
dl
cl
ml
Units of measurement
13.0Numerical Ability
How many odd numbers are there between 151 and 168 ?
Explanation
The odd numbers between 151 and 168 are -
153,155,157,159,161,163,165,167
The total number is 8 .
(i) Find the smallest natural number.
(ii) Find the number of four-digit natural numbers.
Solution
(i) The smallest natural number is 1 .
(ii) The number of four-digit natural numbers is 9000 .
Compare 45967 and 45861.
Explanation
As number of digits are same so starting from the left hand side, we notice that 2 digits are the same.
45967 and 45861
On comparing the digits at the hundred places in both the numbers we find that 9 in
45967 is greater than 8 in 45861.
∴45967>45861
Make the greatest and the smallest four-digit numbers by using different digits such that digit 6 is always in the tens place.
Explanation
We know that the digits written in the descending order are 9,8,7,6,5,4,3,2,1,0.
Keeping 6 in the tens place, we have
Greatest number =9867
Smallest number =1062
Make the smallest and the greatest 5 -digit numbers using the digits 4, 6, 3, 1 and 0 only once.
Express the following in expanded form.
(i) 3,54,039
(ii) 3,85,00,386
Explanation
(i) Place value of 3=3×100000
Place value of 4=4×1000
Place value of 3=3×10
Place value of 5=5×10000
Place value of 0=0×100
Place value of 9=9×1∴ The expanded form of 3,54,029 is
3×100000+5×10000+4×1000+0×100+3×10+9×1.
(ii) Likewise, the expanded form of 3,85,00,386 is
3×10000000+8×1000000+5×100000+0×10000+0×1000+3×100+8×10+6×1.
C
TL
L
T-Th
Th
H
T
0
10,000,000
1,000,000
100,000
10,000
1,000
100
10
1
(i)
3
5
4
0
3
9
(ii)
3
8
5
0
0
3
8
6
The population of Rajasthan is 5,64,73,122, and of Goa is 13,43,998 and of Karnataka is 5,27,33,958. What is the combined population of the three states?
Solution
Population of Rajasthan is 5,64,73,122
Population of Goa is 13,43,998
Population of Karnataka is 5,27,33,958
∴ Total population of three states
=5,64,73,122+5,27,33,958+13,43,998=11,05,51,078
i.e., Eleven crore five lakh fifty-one thousand seventy-eight.
10. What must be added to 34,52,629 to make it equal to 6 crores?
Solution
6 crores =6,00,00,000
∴ Required number =6,00,00,000−34,52,629
6,00,00,000−34,52,6295,65,47,371
=5,65,47,371
11. There are 785 students on roll in a residential public school. If the annual fee per student is Rs. 62,606. What is the total fee collected annually by the school.
Solution
Annual fee of one student = Rs. 62,606
62606
Number of students =785
Total Annual collection of fee
= Rs. 62,606×785= Rs. 4,91,45,710
12. Find the number of pages in a book which has on an average 207 words on a page and contains 201411 words altogether.
Solution
Number of pages =201411÷207
Thus, the number of pages in the book =973.
13. Write the numeral for each of the following numbers:
(i) Ninety-eight crore two lakh seventy five.
(ii) Six million, four hundred and twelve thousand, two hundred and twenty.
Solution:
(i) Ninety-eight crore two lakh seventy-five is 98,02,00,075.
(ii) Six million, four hundred and twelve thousand, two hundred and twenty is 6,412,220.
14. Write the following in Roman numerals:
(i) 52
(ii) 44
(iii) 85
(iv) 49
(v) 99
Explanation
(i) 52=50+2=L+II=LII
(ii) 44=40+4=XL+IV=XLIV
(iii) 85=80+5= LXXX +V= LXXXV
(iv) 49=40+9= XL + IX = XLIX
(v) 99=90+9=XC+IX=XCIX
15. Write the following in Hindu-Arabic numerals:
(i) XLV
(ii) LXIII
(iii) LXXVI
(iv) XCII
(v) XXXVIII
Solution
(i) XLV=XL+V=(50−10)+5=40+5=45
(ii) LXIII =L+X+III=50+10+3=63
(iii) LXXVI =L+XX+VI=50+(2×10)+6=76
(iv) XCII = XC + II =(100−10)+2=90+2=92
(v) XXXVIII = XXX + VIII =(3×10)+8=30+8=38
Explanation
You need to decide whether to round up or down.
Look at the digit in the ones place:
If the ones digit is 5 or more, round up.
If the ones digit is 4 or less, round down.
Start with 18 : The digit in the ones place is 8 and 8 is more than 5 , so round up. 18 rounded up to the nearest ten is 20 .
Next, 43: The digit in the ones place is 3 and 3 is less than 5 , so round down. 43 rounded down to the nearest ten is 40 .
By rounding, you can replace 18×43 with 20×40.
This is much easier to solve: 20×40=800
800 is fairly close to the real answer: 18×43=774
19. Round 25,281 to the nearest hundred.
Explanation
Write the number, and underline the hundreds digit: 25, 281
You're rounding to the nearest hundred, so that's going to be either 25,200 or 25,300.
The digit to the right of the underline is 8 .
That's greater than 5 , so round up. So, 25,281 rounds up to 25,300 , to
the nearest hundred.
Rounding a number to the nearest 1000
To round off a number to the nearest thousand, we get the nearest multiples of 1000 for that number.
Rule : Look at the digit in the hundreds place. If it is 5 or more
Round 4392 to the nearest thousand.
Explanation
20. Round off the following numbers to the nearest tens, hundreds, thousands.
(i) 7848
(ii) 5164
Explanation
(i) 7848 Rounded off to nearest 1078507848 Rounded off to nearest 10078007848 Rounded off to nearest 10008000
(ii) 5164 Rounded off to nearest 1051605164 Rounded off to nearest 10052005164 Rounded off to nearest 10005000
21. Lucas wants to add 3439 and 5482. He doesn't need an exact answer, so he decides to use rounding. Look at Lucas's work below. How could he have found a more accurate answer?
Actual:
+3439+54828921
Rounded to the nearest thousand:
+3000+50008000
Rounded to the nearest hundred:
+3400+55008900
Explanation
Lucas rounded to the nearest thousand, so he got an estimate of 8000 .
If he had rounded to the nearest hundred, he would have got 8900 , which is much closer to the actual 8921.
22. Calculate 2343 +5077. Then check your work by rounding to the nearest hundred.
Solution
Actual sum: 2343
Rounded sum: 2300
+507774207400+5100
23. The answer to the rounded sum is close to the answer to the actualsum, so the answer to the rounded sum is reasonable.
Martin is trying to solve 29.6×9.8. He gets the answer 192.08. Check Martin's answer by rounding to the nearest ten.
Solution
Rounded product : 30×10=300
Martin's answer is a long way from the rounded answer, so it looks like his answer of 192.08 might be wrong.
In fact, 29.6×9.8=290.08
This is much closer to the rounded estimate.
24. Carla has a tall bookshelf and a short bookshelf. When full, the tall bookshelf can hold about 60 books.
Estimate from the picture how many books the small bookshelf will hold.
Explanation
There is no exact number of books you can fit on a bookshelf, because not all books are the same size.
To estimate the answer, compare the bookshelves. The tall one has 3 shelves, and the small one only 2 . All the shelves has the same size, so the small bookshelf will hold around two-thirds the number of books.
So, you can estimate that the small bookshelf will hold about 40 books.
You can estimate if you don't need an exact answer
You don't always need to use an exact figure. Sometimes an estimate is enough.
25. A auto started its journey and reached different places with a speed of 20km/hour. The journey is shown below.
26. (i) Find the total distance covered by the auto from A to D.
(ii) Find the total distance covered by the auto from D to G.
(iii) Find the total distance covered by the auto, if it starts from A and returns back to A.
(iv) Find the difference of distances from C to D and D to E ?
(v) Find out the time taken by the auto to reach
(a) A to B
(b) C to D
(c) E to G
(d) Total journey
Explanation
(i) Total distance covered by the auto from A to D
=4180+3650+2360=10,190km
(ii) Total distance covered by the auto from D to G
=8250+4930+2610=15790km
(iii) Total distance =4180+3650+2360+8250+4930+2610+1120=27100km
(iv) Difference of distances from C to D and D to E
=8250−2360=5890km
(v) (a) 204180=209hrs
(b) 202360=118hrs
(c) 204930+2610=377hrs
(d) speed Totaldistance =2027100=1355hrs
14.0Memory Map
Table of Contents
1.0Introduction to Numbers
2.0Comparing and Building Numbers
2.1Comparing Numbers with the Same Number of Digits
3.0Introducing 6-Digit, 7-Digit and 8-Digit Numbers