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P4 undergoes disproportionation in basic...

`P_4` undergoes disproportionation in basic medium to give `PH_3` (phosphine) and `H_2PO^(ɵ)` (dihydrogen hypophoshite ion). Atomic weight of P is 31.

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To solve the problem of the disproportionation of \( P_4 \) in a basic medium to form \( PH_3 \) (phosphine) and \( H_2PO_2^- \) (dihydrogen hypophosphite ion), we will follow these steps: ### Step 1: Write the overall reaction The disproportionation reaction can be represented as: \[ P_4 \rightarrow PH_3 + H_2PO_2^- \] ...
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Knowledge Check

  • 18 " mL of " 1.0 M Br_(2) solution undergoes complete disproportionation in basic medium to Br^(The hardness of water in terms of ) and BrO_(3)^(ɵ) . Then the resulting solution required 45 " mL of " As^(3+) solution to reduce BrO_(3)^(ɵ) to Br^(ɵ) . As^(3+) is oxidised to As^(5+) which statements are correct?

    A
    `Ew(Br_(2))=(M)/(10)`
    B
    `Ew(Br_(2))=(5M)/(3)`
    C
    Molarity of `As^(+3)=0.4M`
    D
    Molarity of `As^(3+)=0.2M`

  • The equivalent weight of H_3PO_2 ,when it disproportionates into PH_3 and H_3PO_4 , is

    A
    82
    B
    61.5
    C
    33
    D
    20.5

  • Equivalent weight of H_(3)PO_(2) , when it disproportionate into PH_(3) and H_(3) PO_(3) is

    A
    `(5M)/(4)`
    B
    `(7M)/(4)`
    C
    `(3M)/(4)`
    D
    `(9M)/(4)`

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    (a). What is the equivalent weight of H_3PO_2 when it disproportionates into PH_3 and H_2PO_3 ? (b). What ist he equivalent weight of H_3PO_2 when it acts as an acid?

    Balance following equations in proper medium P + OH^(-) +H_(2)O rarr H_(2)PO_(4)^(-) +PH_(3)

    The equivalent weight of H_2Po_2 when it disproprtianates into PH_3 and H_3PO_4 is

    In PO_(4)^(3-) ion the formal charge on the oxygen atom of P-O bond is

    In PO_(4)^(3-) ion, the formal charge on the oxygen atom of P-O bond is

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