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A spherical charged conductor has surfac...

A spherical charged conductor has surface density of charge as `sigma`. The electric field intensity on its surface is `E`. If the radius of the surface is doubled, keeping `sigma` uncharged, what will be the electric field intensity on the new sphere ?

A

`E//2`

B

`E//4`

C

`2 E`

D

`E`

Text Solution

Verified by Experts

The correct Answer is:
d

`E = sigma // epsilon_0` does not depend upon radius if `sigma` is constant.
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