Home
Class 12
PHYSICS
The measurement of an unknown resistance...

The measurement of an unknown resistance R is to be carried out using Wheatstone bridge (see Fig. 2(EP).3). Two students perform an experiment in two way. The first student takes `R_(2)=10 Omega` and `R_(1)=5Omega`. The other student takes `R_(2)=1000Omega` and `R_(1)=500Omega`. In the standard arm, both take `R_(3)=5Omega`. Both find `R=(R_(2))/(R_(1))R_(3)=10Omega` within errors.

A

The errors of measurement of the two students are the same

B

Errors of measurement do depends on the accuracy with which `R_2 and R_1` can be measured

C

If the student uses large values of `R_2 and R_1` The currents through the arms will be feeble. This will make determination of null point accurately more difficult

D

Wheatstone bridge is a very accurate instrument and has no errors of measurement

Text Solution

Verified by Experts

The correct Answer is:
B, C
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTRICAL MEASURING INSTRUMENTS

    CENGAGE PHYSICS|Exercise Integer|8 Videos

  • ELECTRIC POTENTIAL

    CENGAGE PHYSICS|Exercise DPP 3.5|14 Videos

  • ELECTROMAGENTIC INDUCTION

    CENGAGE PHYSICS|Exercise QUESTION BANK|40 Videos

Similar Questions

Explore conceptually related problems

Find the current through the resistance R in Fig if R =10 Omega and R=20Omega .

In Fig. 27-43, the current in resistance 6 is i_(6)= 2.80 A the resistances are R_(1)=R_(2)=R_(3)=2.00 Omega, R_(4)=16.0 Omega, R_(5)=8.00 Omega and R_(6)=4.00 Omega . Wat is the emf of the ideal battery?

Knowledge Check

  • In the given circuit, R_(1) = 10Omega R_(2) = 6Omega and E = 10V, then correct statement is

    A
    Effective resistance of the circuit is `10Omega`
    B
    R Reading of `A_(1)` is 1//2 amp.
    C
    Reading of `A_(2)` is 1//2 amp
    D
    Reading of `A_(3)` is 1//8 amp.

  • In the circuit shown in figure Current through R_(2) is zero if R_(4) = 2 Omega and R_(3) = 4 Omega In this case

    A
    Current through `R_(3)` is 2A
    B
    Current through `R_(4)` is 3A
    C
    both (a) and (b) are correct
    D
    both (a) and (b) wrong

  • In the circuit shown below E_(1) = 4.0 V, R_(1) = 2 Omega, E_(2) = 6.0 V, R_(2) = 4 Omega and R_(3) = 2 Omega . The current I_(1) is

    A
    `1.6 A`
    B
    `1.8 A`
    C
    `1.25 A`
    D
    `1.0 A`

    • Similar Questions

    Explore conceptually related problems

    In the given circuit values are as follows epsi=2V,epsi_(2)=4V,R_(1)=1Omega and R_(2)=R_(3)=1Omega . Calculate the current through R_(1),R_(2) and R_(3)

    Find the currents in the Y connection of 3 resistances R_(1) = 10Omega , R_(2)=20Omega and R_(3)= 30 Omega . When the terminals of R_(1) , R_(3) and R_(3) are maintained at potentials V_(1) = 10V, V_(2) =6V and V_(3) = 15V.

    In the circuit shown in Fig. the emf of the sources is equal to xi = 5.0 V and the resistances are equal to R_(1) = 4.0 Omega and R_(2) = 6.0 Omega . The internal resistance of the source equals R = 1.10 Omega . Find the currents flowing through the resistances R_(1) and R_(2) .

    The potential difference in volt across the resistance R_(3) in the circuit shown in figure, is (R_(1)=15Omega,R_(2)=15Omega, R_(3)=30Omega, R_(4)=35Omega)

    In the given figure, E=12V, R_(1)=3Omega, R_(2)=2Omega" and "r=1Omega . The choose the correct option/s

    Home
    Profile