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Calculate the standard enthalpy of form...

Calculate the standard enthalpy of formation of acetylene from the following data `:`
`C_((g))+O_(2(g))rarr CO_(2(g)),DeltaH^(@)=-393kJ mol^(-1)`
`H_(2(g))+(1)/(2)O_(2(g)) rarr H_(2)O_((l)),DeltaH^(@)=-285.8kJ mol^(-1)`
`2C_(2)H_(2(g))+5O_(2(g))rarr 4CO_(2(g))+2H_(2)O_((l)),DeltaH^(@)=-2598.8kJ mol^(-1)`.

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To calculate the standard enthalpy of formation of acetylene (C₂H₂) from the given reactions, we will use Hess's Law, which states that the total enthalpy change for a reaction is the sum of the enthalpy changes for the individual steps of the reaction. ### Step 1: Write the desired reaction The standard enthalpy of formation of acetylene can be represented by the following reaction: \[ 2C(s) + H_2(g) \rightarrow C_2H_2(g) \] ### Step 2: Identify the given reactions We have three reactions with their respective enthalpy changes: ...
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Calculate the standard enthalpy of formation of acetylena from the following data: C(s)+O_(2)(g)to CO_(2)(g), DeltaH^(@)=-393.5KJmol^(-1) H_(2)(g)+(1)/(2)O_(2)(g)to H_(2)O(l),DeltaH^(@)=-285 .8KJmol^(-1) 2C_(2)H_(2)(g)+50_(2)(g)to 4Co_(2)(g)+2H_(2)O(l0, DeltaH^(@)=-2598.8KJmol^(-1)

Calculate enthalpy of formation of methane (CH_4) from the following data : (i) C(s) + O_(2)(g) to CO_(2) (g) , Delta_rH^(@) = -393.5 KJ mol^(-1) (ii) H_2(g) + 1/2 O_(2)(g) to H_(2)O(l) , Deta_r H^(@) = -285.5 kJ mol^(-1) (iii) CH_(4)(g) + 2O_(2)(g) to CO_(2)(g) + 2H_(2)O(l), Delta_(r)H^(@) = -890.3 kJ mol^(-1) .

Calculate the enthalpy of formation of methane from the following data : C(s) + O_(2)(g) to CO_(2)(g) Delta_(r)H^(@) = -393.5 kJ 2H_(2)(g) + O_(2)(g) to 2H_(2)O(l) Delta_(r)H^(@) = -571.8 kJ CH_(4)(g) + 2O_(2)(g) to CO_(2)(g) + 2H_(2)O(l) Delta_(r)H^(@) = -890.3 kJ

Calculate the standard enthalpy of formation of CH_(3)OH(l) from the following data: CH_(3)OH(l)+3/2O_(2)(g) rarr CO_(2)(g)+2H_(2)O(l), …(i), Delta_(r)H_(1)^(Θ)=-726 kJ mol^(-1) C(g)+O_(2)(g) rarr CO_(2)(g), …(ii), Delta_(c )H_(2)^(Θ)=-393 kJ mol^(-1) H_(2)(g)+1/2O_(2)(g) rarr H_(2)O(l), ...(iii), Delta_(f)H_(3)^(Θ)=-286 kJ mol^(-1)

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