A balloon is ascending at the constant rate of `9.8 m//sec` at a height of `98 m` above the ground a packet is dropped from it. If time taken by the packet to reach the ground is `(1 + sqrt(3lambda))sec`. Find `lambda`.
(Use `g = 9.8 m//s^(2)`)

Answer

`7`

Explanation

The initial velocity of the packet is the same as that of the ballon and is pointing upward. Which is taken as the positive direction. The acceleration due to gravity being in the oppsite direction is taken negative the displacement is also negative since its verticity down.
`U = 9.8 m//sec., a = -g = -9.8 m//s^(2)`
`S = -98 m`
`S = ut + (1)/(2)at^(2) rArr -98 = 9.8t - (1)/(2) 9.8t^(2)`
`t^(2) - 2t - 20 = 0`
`t = 1 +- sqrt(21)`
The accepation solution is `1 + sqrt(21) = 5.585`
The second solution being negative is neglected.