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A particle moves such that its accelerat...

A particle moves such that its acceleration is given by `a = -Beta(x-2)`
Here, `Beta` is a positive constnt and x the x-coordinate with respect to the origin. Time period of oscillation is

A

`(2pi)sqrt(beta)`

B

`2pisqrt(1/beta)`

C

`2pisqrt(beta+2)`

D

`2pisqrt(1/(beta+2))`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • A particle moves such that its acceleration is given by a =- beta (x-2) Here beta is positive constant and x is the position form origin. Time period of oscillation is

    A
    `2pisqrt(beta)`
    B
    `2pi(1)/(sqrt(beta))`
    C
    `2pi sqrt(beta +2)`
    D
    `2pi sqrt((1)/(beta+2))`

  • A particle moves such that acceleration is given by a= -4x . The period of oscillation is

    A
    `pi`
    B
    `(2)/(pi)`
    C
    `(1)/(pi)`
    D
    `2pi`

  • A particle moves so that its acceleration a is give by a=bn where x is displacement from equilibrium position and b is non negative real constant the time period of oscillation of the particle is

    A
    `2pisqrt(b)`
    B
    `(2pi)/b`
    C
    `(2pi)/sqrt(b)`
    D
    `2 sqrt(pi/b)`

    • Similar Questions

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