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In kolbe’s electrolytic synthesis the pO...

In kolbe’s electrolytic synthesis the pOH of solution will be

A

decreases

B

Increases

C

Constant

D

None of these

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The correct Answer is:
To determine the pOH of the solution during Kolbe’s electrolytic synthesis, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Kolbe’s Electrolysis**: - Kolbe’s electrolysis involves the electrolysis of sodium or potassium salts of carboxylic acids in an aqueous solution. 2. **Electrolysis Process**: - When the electrolysis is performed, the carboxylic acid salts dissociate in the solution, and the electrolysis leads to the formation of alkanes, carbon dioxide (CO2), and hydrogen gas (H2). 3. **Formation of KOH**: - During the electrolysis, potassium ions (K⁺) and hydroxide ions (OH⁻) are produced. The hydroxide ions combine with potassium ions to form potassium hydroxide (KOH). 4. **Effect on pH**: - The formation of KOH increases the basicity of the solution. Since KOH is a strong base, its presence will increase the pH of the solution. 5. **Relationship between pH and pOH**: - The relationship between pH and pOH is given by the equation: \[ pH + pOH = 14 \] - If the pH increases due to the formation of KOH, then the pOH must decrease to maintain the constant sum of 14. 6. **Conclusion**: - Therefore, during Kolbe’s electrolytic synthesis, the pOH of the solution decreases as the pH increases. ### Final Answer: The pOH of the solution will decrease during Kolbe’s electrolytic synthesis. ---
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Knowledge Check

  • During Kolbe's electrolytic method, the pH of aqueous solution of salt of acid

    A
    increases
    B
    decreases
    C
    remains the same
    D
    first decreases then increases
  • In a buffer solution consisting of a mixture of weak base and its salt, the ratio of salt to base is increases 10 times , the pOH of the solution will

    A
    Increase by one units
    B
    Decrease by one units
    C
    Increase by ten units
    D
    Decrease by ten units
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    A
    `CH_(3)COONa`
    B
    `(KOOC-CH_(2)-CH_2-COOK)`
    C
    `underset(KOOC-CH=HC-COOK)`
    D
    All of these
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