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Reaction of one molecule of HBr with one...

Reaction of one molecule of HBr with one molecule of 1,3-butadiene at `40^(@)`C gives predominantly.

A

1–bromo–2–butene under thermodynamically controlled conditions

B

3–bromobutene under kinetically controlled conditions

C

1–bromo–2–butene under kinetically controlled conditions

D

3–bromobutene under thermodynamically controlled conditions

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • Reaction of one molecule of HBr wit one moleculae 1,3-butadiene at 40^(@)C gives predominnantly

    A
    3-bromobutene under kinetically controlled conditions
    B
    1-bromo-2-butene under thermodynamically controlled conditions
    C
    3-bromobutene under thermodynamically controlled conditions
    D
    1-bromo-2-butene under kinetic controlled conditions

  • Mass of one molecule of ammonia is

    A
    `(1)/(6.022xx 10^(23))`
    B
    (34)/(6.022xx10^(23))`
    C
    `17)/(6.022xx10^(23))`
    D
    none of these

  • Reduction of one molecule of nitrogen into 2 molecules of NH_(3) consumes

    A
    4 molecules of ATP
    B
    16 molecules of ATP
    C
    56 molecules of ATP
    D
    38 molecules of ATP

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