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CH(3)-C-=C-HrarrCH(3)-C-=C-CH(3) Above...

`CH_(3)-C-=C-HrarrCH_(3)-C-=C-CH_(3)`
Above conversion can be achieved by

A

`NaNH_(2), CH_(3)–I`

B

`NaH, CH_(3)–I`

C

`Na, CH_(3)–I`

D

All

Text Solution

Verified by Experts

The correct Answer is:
D
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