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NCERT Solutions
Class 6
Maths
Chapter 6 Perimeter And Area
Exercise 6.2

NCERT Class 6 Maths Ch. 6 Perimeter and Area Other Exercises:-

Exercise 6.1

Exercise 6.2

Exercise 6.3

NCERT Solutions for Class 6 Maths Other Chapters:-

Chapter 1: Patterns in Mathematics

Chapter 2: Lines and Angles

Chapter 3: Number Play

Chapter 4: Data Handling and Presentation

Chapter 5: Prime Time

Chapter 6: Perimeter and Area

Chapter 7: Fractions

Chapter 8: Playing With Construction

Chapter 9: Symmetry

Chapter 10: The Other Side of Zero

Frequently Asked Questions

Exercise 6.2 includes problems dealing with determining areas of regular shapes using formulas.

Area is important because it allows students to solve relevant real-life measurement problems, and learn skills that will help in later topics.

It allows students to practice important geometry questions that are commonly asked in the CBSE exam.

Area-related questions are a good test of logical thought, which is very important for olympiad exams.

They provide clear steps and explanations that help students learn the correct way to approach problems in this chapter.

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NCERT Solutions Class 6 Maths Chapter 6 Perimeter and Area Exercise 6.2

Class 6 Maths NCERT Solutions Chapter 6 – Exercise 6.2 develops understanding of the area of rectangles using the formula l × b. Students calculate missing dimensions, find tiling costs, determine the maximum number of trees in a field, and split irregular shapes into rectangles to calculate area. The tangram section strengthens conceptual understanding by comparing areas of shapes and expressing total area in terms of smaller units.

Students can access the complete NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.2 in a free pdf format on this page. The solutions have been explained simply in easy steps, so that they could learn at their own pace. These solutions can be used to revise the chapter and understand the methods used to solve the questions.

1.0Download NCERT Solutions Class 6 Maths Chapter 6 Perimeter and Area Exercise 6.2: Free PDF

Exercise 6.2 is about using standard formulas to calculate the area of squares and rectangles. It reinforces the concepts of basic geometry and measurement. You can find the entire NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.2 and download the free PDF to help with preparation for exams.

Chapter 6 Perimeter and Area - Exercise 6.2

2.0Key Concepts Covered in Exercise 6.2 Class 6 Maths

  • Area of rectangle: l × b: Calculating the surface covered by a rectangle using its length and breadth.
  • Finding width from given area: Determining the missing dimension of a rectangle when its area and one side are known.
  • Cost calculations using area: Solving practical problems involving costs of tiles, flooring, or covering surfaces.
  • Splitting figures into rectangles: Breaking complex shapes into smaller rectangles to calculate total area easily.
  • Tangram-based area comparison: Comparing the areas of different shapes using tangram pieces as unit shapes.

3.0NCERT Solutions Class 6 Chapter 6 Perimeter and Area: All Exercises

Chapter 4 Perimeter and Area : Exercise 6.1

Chapter 4 Perimeter and Area : Exercise 6.2

Chapter 4 Perimeter and Area : Exercise 6.3

4.0NCERT Class 6 Maths Chapter 6 Perimeter and Area Exercise 6.2: Detailed Solutions

6.2 Area

  1. The area of a rectangular garden 25 m long is 300 sq m . What is the width of the garden? Sol. Given, area of rectangular garden =300 sq. m And length =25 m Area of rectangular field =ℓ×b ⇒300=25×b
    ⇒b=12 m
  2. What is the cost of tiling a rectangular plot of land 500 m long and 200 m wide at the rate of ₹ 8 per hundred sq m?
    Sol. Length =500 and breadth =200 m Hence the area of the rectangular plot = length × breadth =500×200 =1,00,000 m2 Now cost of tilling a rectangular plot =1008​ Hence the cost of tilling 1,00,000 sq. m of rectangular plot =1008​×100000=₹8,000
  3. A rectangular coconut grove is 100 m long and 50 m wide. If each coconut tree requires 25 sq. m, what is the maximum number of trees that can be planted in this grove?
    Sol. Area of rectangular coconut grove =100×50=5000 sq. m Given each coconut tree requires 25 sq. m Then the maximum number of trees that can be planted in this grove =255000​=200 trees
  4. By splitting the following figures into rectangles, find their areas (all measures are given in metres):
    Sol. (a) Area of the figure = Area of sq. A+ Area of sq. B+ Area of sq. C+ Area of sq. D =(3×3)+(1×7)+(5×2)+(1×2) =9+7+10+2 =28 m2
    (b) Area of the figure = Area of rectangle E+ Area of rectangle F+ Area of rectangle G =(1×2)+(1×5)+(1×2) =2+5+2 =9 m2
    Cut out the tangram pieces given at the end of your textbook.
  5. Explore and figure out how many pieces have the same area. Sol. There are two pieces ( A and B ) that have the same area.
  6. How many times bigger is Shape D as compared to Shape C? What is the relationship between Shapes C, D and E? Sol. Shape D is two times bigger than shape C . Clearly from the figure, the area of shapes C and E is equal to the area of shape D.
  7. Which shape has more area: Shape D or F? Give reasons for your answer. Sol. Since the medium triangle and the square are each made up of two small tangram triangles, they each have an area 2x that of the small triangle. Hence both have the same area.
  8. Which shape has more area: Shape F or G? Give reasons for your answer. Sol. Since the medium triangle and the rhomboid are each made up of two small tangram triangles, they each have an area 2x that of the small triangle. Hence both have the same area.
  9. What is the area of Shape A as compared to Shape G? Is it twice as big? Four times as big? Hint: In the tangram pieces, by placing the shapes over each other, we can find out that Shapes A and B have the same area, Shapes C and E have the same area. You would have also figured out that Shape D can be exactly covered using Shapes C and E, which means Shape D has twice the area of Shape C or shape E , etc. Sol. Shape A has twice the area of shape G.
  10. Can you now figure out the area of the big square formed with all seven pieces in terms of the area of Shape C? Sol. Let's say the area of C=x Area of D= Area of 2C=2x Area of E= Area of C=x Area of F= Area of 2C=2x Area of G= Area of 2C=2x Area of A= Area of 2F=2×2x=4x Area of B= Area of A=4x Hence total area of big shape = Area of A+B+C+D+E+F+G =4x+4x+x+2x+x+2x+2x =16x =16C That means the area of a big square is 16 times the area of shape C.
  11. Arrange these 7 pieces to form a rectangle. What will be the area of this rectangle in terms of the area of Shape C now? Give reasons for your answer. Sol. The tangram rectangle with all 7 pieces is a tangram square with 5 pieces extended with two big triangles. All seven tans fit together to form a rectangle. Hence area of this rectangle in terms of Shape C is 16 small triangles.
  12. Are the perimeters of the square and the rectangle formed from these 7 pieces different or the same? Give an explanation for your answer. Sol. The perimeter of the square is equal to the square formed from these 7 pieces because these are the arrangements of pieces.

5.0Key Features and Benefits for Class 6 Maths Chapter 6 Exercise 6.2

  • This exercise Includes questions on finding areas of squares and rectangles with easy-to-recall formulas.
  • All questions are based on the latest NCERT syllabus for Class 6 as prescribed by the CBSE.
  • It allows students to understand accurately how to measure space inside flat shapes.
  • Practicing NCERT solutions will help you have better accuracy and confidence in preparation for your maths exam and other exams like the Olympiads.
  • Students can use the step-by-step solutions in order to learn easily and know precise methods of problem-solving.