The factorisation is a very important mathematical concept and involves writing a number or an algebraic expression in terms of its factors. Factors of any number or expression can divide it without leaving any remainder.
What is Factorisation?
Factorisation is a process where we can write any algebraic expression as a product of factors. These factors may be numbers, algebraic variables, or algebraic expressions.
x2 + 5 x + 6 = (x + 2)(x + 3)
In the given example, on the left-hand side, we have an unfactorised equation, and on the right-hand side, there are two factors given in the equation in binomial form.
Key Term
x2 + 6x
x2 = x . x
6x = 6 . x
The common factor here is x.
5ab + 10a + 5b + 10
After regrouping,
5ab + 5b + 10a + 10
5b(a+1) + 10(a+1)
Now factor out (a + 1)
(a + 1)(5b + 10)
There are some formulas present in maths that are used to factor out polynomials in the factorisation. There are three identities that will be used in class 8.
= (a+b)(a+b)
= a(a+b) + b(a+b)
= a2 + ab + ab + b2
= a2 + 2ab + b2
= (a - b)(a - b)
= a(a-b) -b(a-b)
= a2 – ab – ab + b2
= a2 – 2ab + b2
= a(a-b) +b(a-b)
= a2 – ab + ab – b2
= a2 – b2
Solved Examples Related to Identities
Example: Expand using identity: x2 + 10x + 25
Compare Identity 1 to this question
a2 + 2ab + b2 = x2 + 2.(x).5 + 52
= (x + 5)2
= (x + 5)(x + 5)
Example: Expand using identity: x2 – 8x + 16
Compare the question with Identity 2
a2 – 2ab + b2 = x2 – 2.(x).4 + 42
= (x – 2)2
= (x – 2)(x – 2)
Example: Expand using identity: x2 – 36
Compare the question with identity 3
a2 – b2 = x2 – 62
= (x + 6)(x – 6)
Example: Evaluate using suitable identities.
Solution:
a) 952 = (100-5)2 = (100)2- 21005+(5)2
= 10000 - 1000 + 25 = 925
b) 1962 - 1442 = (196+144)(196-144)
= (340)(52) = 17680
(x+a)(x+b)
x(x+b) + a(x+b)
x2 + xb + ax +ab
x2 + x(a+b) + ab
To elaborate more, let’s have a look at the examples below.
Example: Expand using identity: x2 - 4x - 12
= x2 - (6x - 2x) - 12
= x2 - 6x + 2x - 12
= x(x - 6) + 2(x - 6)
= (x + 2)(x - 6)
Example: Expand the following equation: (x+5)(x+3)
Solution:
With the help of the above identity, a = 5, and b=3
Put the value of a and b in x2 + x(a+b) + ab
x2 + x(5+3) + 5 3
x2 + 8x +15
Example: Factories: x2- 4x- 12
= x2 - (6x - 2x) - 12
= x2 - 6x + 2x - 12
= x(x - 6) + 2(x - 6)
= (x+2)(x - 6)
Note: Remember to use the symbols carefully, as one mistake can affect the whole answer.
In Maths, for division in algebra, we first factorise both numerator and denominator in their irreducible factors, then cancel the common terms from the equation. Different types of division are as follows:
Division of a Monomial by Another Monomial
10x2/5x =
Division of Polynomial by Monomial
Division of Polynomial by Polynomial
(Session 2025 - 26)